Answer:
10.6 moles of CO₂ are produced in this combustion
Explanation:
The combustion reaction is:
2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (g)
We assume the ethane as the limiting reactant because the excersise states that the O₂ is in excess.
We make a rule of three:
2 moles of ethane can produce 4 moles of CO₂
Therefore 5.30 moles of ethane will produce (5.3 . 4) /2 = 10.6 moles
Both elements and compounds are pure substances. While elements are not made of simpler substances, compounds are made up of two or more chemical elements that are chemically combined.
Answer: 2.223
Explanation:
HClO4, also known as perchloric acid, is a very strong. This means we can assume that complete dissociation occurs.
This means that:
[H+] = [HClO4] = <span>0.00598
pH = -log[H+]
pH = -log[</span><span>0.00598] = 2.223
Note: The base of the log is 10 (conventionally we don't write the base if it is 10)</span>
