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FinnZ [79.3K]
3 years ago
15

Part A

Chemistry
1 answer:
jeka943 years ago
6 0

The largest risks while designing a model to withstand a village include that the model does not mitigate the effects of the tsunami or only mitigates the effects partially, which would cause damages to the homes.

Designing a model to withstand the effect of any natural phenomenon such as an earthquake, fire or tsunami is not an easy task and will require the following cycle:

  • Designing the model.
  • Testing the model.
  • Making changes or designing a new model.

In the case of a model for tsunamis, it is likely the following problems occur:

  • The model does not protect the houses from tsunamis.
  • The model does not protect the houses completely.

This would lead to negative effects such as:

  • Damages in the houses.
  • Dead or injured people.
  • Destruction of infrastrcture.

Note: This question is incomplete because the context is missing; here is the missing part.

Protecting Your Model Village from Tsunamis this task, you will design a model village to withstand the effects of a tsunami.

Learn more about tsunami in: brainly.com/question/1126317

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16.4 mL of 0.135 M NaOH is used to neutralize 46.9 mL of HCl. The concentration of the HCl solution is ____ M (3 decimal places)
marshall27 [118]

The concentration of the HCl solution is 0.047 M.

Explanation:

Data given about acid and base:

volume of acid Vacid = 46.9 ml

molarity of acid =?

volume of the base (NaOH) = 16.4 ml

molarity of the base = 0.135 M

To know the concentration of the acid in this reaction, the formula used in titration  is used. It is

Macid X Vacid = Mbase X Vbase

the formula is rewritten as:

Macid = \frac{Mbase X Vbase}{Vacid}

putting the values in the equation:

Macid = \frac{0.135 X 16.4}{46.9}

          = 0.047 M

the concentration of the acid i.e HCl in the solution is of 0.047 M.

5 0
4 years ago
What does a cell do to a substance in Endocytosis
8090 [49]
Endocytosis is a type of bulk transport which involves the movement of large particles through the membrane in and out
3 0
4 years ago
The isotopic mass of ²¹⁰₈₆Rn is 209.989669amu. When this nuclide decays by electron capture, it emits 2.368 MeV. What is the iso
zaharov [31]

Starting from the radon mass, add the mass of the electron, and subtract the mass attributable to the gamma radiation <u>(931 Mev = 1 amu).</u>

<u></u>

<h3>What is gamma radiation?</h3>

Gamma radiation (gamma rays) refers to the part of the electromagnetic spectrum with the most energy and shortest wavelength. Astrophysicists define gamma radiation as any radiation with an energy above 100 keV. Physicists define gamma radiation as high-energy photons released by nuclear decay.

Using the broader definition of gamma radiation, gamma rays are released by sources including gamma decay, lightning, solar flares, matter-antimatter annihilation, the interaction between cosmic rays and matter, and many astronomical sources. Gamma radiation was discovered by Paul Villard in 1900.

Gamma radiation is used to study the universe, treat gemstones, scan containers, sterilize foods and equipment, diagnose medical conditions, and treat some forms of cancer.

Learn more about gamma radiation

brainly.com/question/20799041

#SPJ4

5 0
2 years ago
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
4 years ago
A solution of barium nitrate has 61.2g of barium nitrate in 1 liter of solution. How many mg of barium are there in 7.5 quarts
Nuetrik [128]

Answer:

220.44g Ba²⁺ ions in solution

Explanation:

Given parameters:

Mass of barium nitrate = 61.2g

Volume of solution = 1 liter

Unkown:

Mass of barium in 7.5quarts of solution?

Solution

We must first convert quarts to its liter equivalence:

                    1 quarts = 0.95 liter

                   7.5 quarts = 0.95 x 7.5; 7.125liter

Now, let us find the mass of barium nitrate in a solution of 7.125liter:

        Given:

            1 liter of solution contains 61.2g of barium nitrate:

          7.125 liter will contain  7.125 x 61.2 = 436.05g of barium nitrate.

The formula of the compound is Ba(NO₃)₂:

  In solution we have  Ba²⁺ + NO₃⁻

                Ba(NO₃)₂ → Ba²⁺ + 2NO₃⁻

 

Number of moles of Ba(NO₃)₂ = \frac{mass of Ba(NO₃)₂}{Molar mass of Ba(NO₃)₂}

Molar mass of Ba(NO₃)₂ = 137 + 2[14 + 3(16)] = 271g/mol

Number of moles of Ba(NO₃)₂ = \frac{436.05}{271} = 1.609mole

      1 mole of Ba(NO₃)₂ will produce 1 mole of Ba²⁺ ions in solution

    therefore, 1.609mole of Ba(NO₃)₂ will also yield 1.609mole of Ba²⁺ ions in solution

Mass of Ba²⁺ ions = Number of moles of Ba²⁺ ions  x molar mass of Ba²⁺ ions

Mass of Ba²⁺ ions = 1.609 x 137 = 220.44g

3 0
3 years ago
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