10 fewer people
After 15 people get off, 9 get on, 4 get off leaving 5. 5 is 10 less than 15.
Complete question:
Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.
Answer:
11/288
Step-by-step explanation:
We are given:
Box 1: ( 4White, ORed)
Box 2: (3White, 1Red)
Box 3: (2White, 2 Red)
We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.
Since there is no red ball in Box 1, there is no way 2 red balls will come out from Box1.
Our Event, E = getting 2 red balls.
Now Box 1 is ruled out, we have:
P[E(B1)]= 0
P[E/B3)] = (2 2) / (4 2)
= 1/6
If box 2 is chosen, 2 balls are extracted with replacement. Therefore for Box 2:
P(E/B2) = (1/4) *(1/4)
= 1/16
Therefore probability that 2 balls extracted are red, we have:
P(E)=P(E/B1) P(B1) + P(E/B2) P(B2)+P(E/B3) P(B3)
= 11/288
2x^2 + 5x + 2 = (2x + 1)(x + 2)
2w^2 + 5w - 3 = (2w -1)(w + 3)
3a^2 + 14a + 8 = (3a + 2)(a + 4)
30z^2 - 23z + 2 = (10z - 1)(3z - 2)
8y^2 + 23y -3 = (8y - 1)(y + 3)
not sure about last one sorry
Answer:
I believe this would be the correct answer.
Answer:
r = 6.146
Step-by-step explanation:
formula for the volume is 4/3πr³
v = 4/3πr³ <u>we adjust the equation for the r</u>
r = ∛3v/4π
r= ∛3*972/4*3.14
r = 6.146