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ElenaW [278]
3 years ago
9

If someone is 1.83 meters tall, what is his or her approximate height in inches

Mathematics
1 answer:
suter [353]3 years ago
4 0

1.83 meters is approximately 72 inches

Hope this helps you

-AaronWiseIsBae

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(3x²+6)(3x²-6) please help
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Answer:

9x^4 -36

Step-by-step explanation:

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2 years ago
Multiply the numbers and simplify the answer: 3 x 1- 3/4
madam [21]
\underbrace{3\times1}_{first}-\frac{3}{4}=3-\frac{3}{4}=2\frac{1}{4}

3\times1\frac{3}{4}=3\times\frac{1\times4+3}{4}=3\times\frac{4+3}{4}=\frac{3}{1}\times\frac{7}{4}=\frac{3\times7}{4}=\frac{21}{4}=\frac{20+1}{4}=\frac{20}{4}+\frac{1}{4}\\\center\boxed{=5\frac{1}{4}}
5 0
3 years ago
From 42 acres to 72 acres (round to the nearest percent
guajiro [1.7K]

Answer:

42 acres to 72 acres, there is an increase of 30 acres

percentage wise

72-42=30

30/72=.4166...

therefore there is also a 41.6% increase

Step-by-step explanation:

71.42 Percentage change:×100%

Now, the change is given from 42 acres to 72 acres, therefore

Change= 72-42=30

⇒Percentage change= ×100%

                                   = 71.42

8 0
3 years ago
Suppose that X1 and X2 are independent random variables each with a mean μ and a variance σ^2. Compute the mean and variance of
Deffense [45]

Mean:

E[Y] = E[3X₁ + X₂]

E[Y] = 3 E[X₁] + E[X₂]

E[Y] = 3µ + µ

E[Y] = 4µ

Variance:

Var[Y] = Var[3X₁ + X₂]

Var[Y] = 3² Var[X₁] + 2 Covar[X₁, X₂] + 1² Var[X₂]

(the covariance is 0 since X₁ and X₂ are independent)

Var[Y] = 9 Var[X₁] + Var[X₂]

Var[Y] = 9σ² + σ²

Var[Y] = 10σ²

5 0
3 years ago
Victoria is 4 years older than her neighbor. The sum of their ages is no more than 14 years.
marysya [2.9K]
Victoria is 9. Her neighbor is 5.
7 0
3 years ago
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