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Zepler [3.9K]
4 years ago
13

Which of the following expressions is not equal to 0.00055? 55 • 10-5 5.5 • 10-4 5.5 • 104 0.55 • 10-3

Mathematics
2 answers:
frozen [14]4 years ago
5 0

You can put each into standard form to see whether they have the right value.

5.5·10⁴ = 55,000 ≠ 0.00055

EleoNora [17]4 years ago
3 0

Answer:

(C)

Step-by-step explanation:

The given expression is :

0.00055

which on simplifying, we get

\frac{55}{100000}=55{\times}10^{-5}

The given expression can be easily rewritten as:

5.5{\times}10^{-4} and 0.55{\times}10^{-3}

but 5.5{\times}10^{4}=55000{\neq}0.00055

Thus, Option (C) is the expression which is not equal to the given expression.

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Two cyclists start from the same location and ride in opposite directions, one riding at 15 mph and the other
velikii [3]

Answer:

40 minutes (I think)

Step-by-step explanation:

Calculate the time into minutes

15mph-0.25mpm

18mph-0.3mpm

add them together to find out how far they go combined each minute

0.55

divide 22 by 0.55 to find the total time

40 minutes

4 0
3 years ago
Write an expression for this problem
bearhunter [10]

Answer:

Do it

Step-by-step explanation:

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5 0
3 years ago
Please help me to prove this!​
Sophie [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B = C                → A = C - B

                                          → B = C - A

Use the Double Angle Identity:     cos 2A = 2 cos² A - 1

                                             → (cos 2A + 1)/2 = cos² A

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · 2 cos [(A - B)/2]

Use Even/Odd Identity: cos (-A) = cos (A)

<u>Proof LHS → RHS:</u>

LHS:                     cos² A + cos² B + cos² C

\text{Double Angle:}\qquad \dfrac{\cos 2A+1}{2}+\dfrac{\cos 2B+1}{2}+\cos^2 C\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg(2+\cos 2A+\cos 2B\bigg)+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\dfrac{1}{2}\bigg(\cos 2A+\cos 2B\bigg)+\cos^2 C

\text{Sum to Product:}\quad 1+\dfrac{1}{2}\bigg[2\cos \bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A-2B}{2}\bigg)\bigg]+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\cos (A+B)\cdot \cos (A-B)+\cos^2 C

\text{Given:}\qquad \qquad 1+\cos C\cdot \cos (A-B)+\cos^2C

\text{Factor:}\qquad \qquad 1+\cos C[\cos (A-B)+\cos C]

\text{Sum to Product:}\quad 1+\cos C\bigg[2\cos \bigg(\dfrac{A-B+C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B-C}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+(C-B)}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-(C-A)}{2}\bigg)

\text{Given:}\qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+A}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-B}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1+2\cos C \cdot \cos A\cdot \cos (-B)

\text{Even/Odd:}\qquad \qquad 1+2\cos C \cdot \cos A\cdot \cos B\\\\\\.\qquad \qquad \qquad \quad =1+2\cos A \cdot \cos B\cdot \cos C

LHS = RHS: 1 + 2 cos A · cos B · cos C = 1 + 2 cos A · cos B · cos C   \checkmark

5 0
3 years ago
Pleasee help asap!! marking brainiest!!
Varvara68 [4.7K]

Answer:

(-1, 4) , (0, 6), (1, 9), (2, 13.5)

Step-by-step explanation:

7 0
3 years ago
How many x-intercepts would the function shown below have?<br> f(x) = -5x (2x + 1)? (x² – 6)(x² + 9)
BabaBlast [244]

Step-by-step explanation:

Here we have

f

(

x

)

=

2

x

2

(

x

2

−

9

)

, which can be factorized as

f

(

x

)

=

2

x

2

(

x

+

3

)

(

x

−

3

)

As there is no common factor between numerator and denominator, there s no hole.

Further vertical asymptotes are

x

=

−

3

and

x

=

3

and as

f

(

x

)

=

2

x

2

(

x

2

−

9

)

=

2

1

−

9

x

2

, as

x

→

∞

,

f

(

x

)

→

2

, hence horizontal asymptote is

y

=

2

.

Observe that

f

(

−

x

)

=

f

(

x

)

and hence graph is symmetric w.r.t.

y

-axis. Further as

x

=

0

,

f

(

x

)

=

0

. Using calculas we can find that at

(

0

,

0

)

there is a local maxima as

d

y

d

x

=

−

36

x

(

x

2

−

9

)

2

and at

x

=

0

it is

0

. Further while for

x

<

−

3

and

x

>

3

, function is positive, for

−

3

<

x

<

3

function is negative.

Now take a few values of

x

say

{

−

10

,

−

7

,

−

4

,

−

2

,

−

1

,

1

,

2

,

4

,

7

,

10

}

and corresponding values of

f

(

x

)

are

{

2

18

91

,

2

9

20

,

4

4

7

,

−

1

3

5

,

−

1

4

,

−

1

4

,

−

1

3

5

,

4

4

7

,

2

9

20

,

2

18

91

}

5 0
3 years ago
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