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Aneli [31]
3 years ago
15

A piece of paper in the shape of an equilateral triangle with side length 3 and a circular piece of paper with radius 1 are glue

d together so that their centers coincide. How long is the outer perimeter of the resulting 2-dimensional shape?

Mathematics
2 answers:
bixtya [17]3 years ago
3 0

Answer:

Outer perimeter of the resulting 2-dimensional shape will be 18.84 units

Step-by-step explanation:

From the figure, we could see

AE =  FB = 1

And  minor arc EF  

=> \frac{2 \pi (1) }{6}  

=>= \frac{2 \pi}{ 6}

=>= \frac{ \pi}{ 3}

So by symmetry the perimeter  is

=>3(2 + \frac { \pi}{3} )

=>3(\frac {6 \pi}{3} )

=>6 \pi

=> 6 \times 3.14

=> 18.84 units

aev [14]3 years ago
3 0

Answer:

6+pi or 9.14

Step-by-step explanation:

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A new shopping mall records 120 total shoppers on their first day of business. Each day after that, the number of shoppers is 10
Marta_Voda [28]

Answer:

1138

Step-by-step explanation:

From the information given:

We can represent it perfectly in an exponential form:

m  = p(q)^x

where;

p = initial value = 120

q = base of the exponential form

q = 1 + r

here; r = rate in decimal = 10% = 0.1

Then q can now be = 1 + 0.1 = 1.1

Replacing it into the exponential form, we get:

m = 120(1.1)^x

where;

x = number of days and m = number of shoppers

Thus:

For the first day:

m = 120(1.1)^x

m = 120

For the second day:

m = 120(1.1)^1

m = 132

For the third day:

m = 120(1.1)^2

m = 145.2

For the fourth day

m = 120(1.1)^3

m = 159.72

For the  fifth-day

m = 120(1.1)^4

m = 175.692

For the sixth-day

m = 120(1.1)^5

m = 193.2612

For the seventh-day

m = 120(1.1)^6

m = 212.58732

Thus; the total numbers of shoppers for the first 7 days is:

= 120+ 132 + 145.2 + 159.72 + 175.692+193.2612+212.58732

= 1138.46052

≅ 1138

6 0
3 years ago
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
3 years ago
A bar of copper has a mass of 216 g and a volume of 24 cm. what is the density of copper
Karo-lina-s [1.5K]
This is how I found the answer

3 0
3 years ago
What number should be added to -20 to get the sum of 36?
DochEvi [55]

36 - (-20) = 56

SO the number that should be added to -20 to get the answer of 36 is 56.

Hope this helps! Mark as Brainliest please! :)))

4 0
3 years ago
Read 2 more answers
Find the measure of an angle that is four hundred eighty-five less than four times its supplement.
Ludmilka [50]
Is 121.25 because 485 divided by 4 is 121.25
4 0
3 years ago
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