Question

A piece of paper in the shape of an equilateral triangle with side length 3 and a circular piece of paper with radius 1 are glued together so that their centers coincide. How long is the outer perimeter of the resulting 2-dimensional shape?

Answer 1

Answer:

Outer perimeter of the resulting 2-dimensional shape will be 18.84 units

Step-by-step explanation:

From the figure, we could see

AE =  FB = 1

And  minor arc EF  

=> $\frac{2 \pi (1) }{6}$  

=>$= \frac{2 \pi}{ 6}$

=>$= \frac{ \pi}{ 3}$

So by symmetry the perimeter  is

=>$3(2 + \frac { \pi}{3} )$

=>$3(\frac {6 \pi}{3} )$

=>$6 \pi$

=> $6 \times 3.14$

=> 18.84 units

Answer 2

Answer:

6+pi or 9.14

Step-by-step explanation: