M−4+m−5 how do I solve this ?

Length:
1 inch (in) = 2.54 centimeters (cm) exactly
1 foot (ft) = 0.305 meters (m)
1 yard (yd) = 0.914 meters (m)
1 mile (mi) = 5280 feet (ft) = 1.61 kilometers (km)
1 centimeter (cm) = 0.394 inches (in)
1 meter (m) = 100 centimeters (cm) = 39.4 inches (in) = 3.28 feet (ft) = 1.09 yards (yd)
1 kilometer (km) = 1000 meters (m) = 0.621 miles (mi)
1 rod = 16.5 feet (ft) = 5.5 yards (yd) = 5.03 meters (m)
1 astronomical unit (AU) = 1.50 x 108 kilometers (km) = 9.29 x 107 miles (mi)
1 light year (LY) = 9.461 x 1012 kilometers ( km) = 5.88 x 1012 miles (mi) = 0.307 parsec
1 parsec = approximately 3.26 light years (LY)

Area = length x width
1 square inch (in2) = 0.00694 square feet (ft2 = 6.45 square centimeters, cm2
1 square foot, (ft2) = 144 square inches (in2 = 0.0929 square meters, m2
1 square yard (yd2 = 1296 square inches (in2 = 9 square feet (ft2 = 0.836 square meters (m2
1 square mile (mi2 = 640 acres = 2.59 square kilometers (km2
1 acre = 160 square rods = 43,560 square feet (ft2) = 0.405 hectares
1 hectare = 10,000 square meters (m2 = 100 ares = 2.47 acres
1 square rod = 30,25 square yards (yd2 = 25.29 square meters (m2
1 are = 100 square meters (m2 = 0.01 hetares = 119.6 square yards (yd2

Volume = length x width x height
1 cubic inch (in3) = 0.000579 cubic feet (ft3) = 16.4 cubic centimeters (cm3)
1 cubic foot (ft3) = 1728 cubic inch (in3) = 0.0283 cubic meters (m3)
1 cubic yard (yd3) = 27 cubic feet (ft3) = 4.65 x 104 cubic inch (in3) = 0.765 cubic meters (m3)
1 cubic meters (m3) = 106 cubic centimeters (cm3) = 1,000 liters (L) = 35.3 cubic feet (ft3)
1 quart (qt) = 2 pints (pt) = 946 milliliters (mL) = 0.946 liters (L)
1 gallon (gal) = 4 quarts = 231 cubic inch (in3) = 3.79 liters (L)
1 liter (L) = 1000 cubic centimeters (cm3) = 1.06 quarts (qt) = 0.265 gallons (gal)

Mass
1 slug = 14.6 kilograms (kg)
1 kilogram (kg) = 1,000 grams = 0.0685 slugs
1 atomic mass unit (u) = 1.66 x 10-27 kilogram (kg) =1.66 x 10-24
1 electron mass = 9.11 x 10-31 kilogram (kg) = 9.11 x 10-28 grams (g) = 5.46 x 10-4 atomic mass unit (u)
1 proton mass = 1.00728 atomic mass unit (u)
1 neutron mass = 1.00866 atomic mass unit (u)

Conversion Between Weight and Mass on Earth
A slug is the mass unit in the British system and is equal to 32.2 pounds (lb)
A kilogram weighs 9.81 newtons (N) or 2.21 pounds (lb)
A mass of one (1) gram (g) weighs 981 dynes or 0.0353 ounces (oz)
A one (1) ounce weight has a mass 28.4 grams (g) or 0.0284 kilograms (kg)
A one (1) pound weight has a mass of 454 grams (g) or 0.454 kilograms (kg)
A metric ton has a mass of 1,000 kilograms (kg)
A one (1) ton (regular) weight has a mass of 2,000 pounds (lb)

Velocity and Speed = distance/time
1 ft/s (ft s-1) = 0.305 m/s (m s-1)
1 mi/hr (mi hr-1) = 1.47 ft/s (ft s-1) = 1.61 km/hr (km hr-1) = 0.447 m/s (m s-1)
1 m/s (m s-1) = 100 cm/s (cm s-1) = 3.28 ft/s (ft s-1)
1 km/hr (km hr-1) = 0.278 m/s (m s-1) = 0.621 mi/hr (mi hr-1) = 0.912 ft/s (ft s-1)
Speed of light in a vacuum = 3.00 x 108 m/s (m s-1) = 3.00 x 1010 cm/s (cm s-1) = 186,000 mi/s (mi s-1)
Speed of sound in air at 0 oC (32 oF) = 331 m/s (m s-1) = 1090 ft/s (ft s-1) = 41 mi/hr (mi hr-1)

Acceleration = velocity / time
1 ft/s2 = 0.305 m/s2 = 30.5 cm/s2
1 mi/hr/s = 1.47 ft/s2 = 1.61 km/hr/s = 0.447 m/s2
1 m/s2 = 100 cm/s2 = 3.28 ft/s2
Acceleration due to gravity on Earth = 9.81 m/s2 = 981 cm/s2 = 32.2 ft/s2

Force = mass x acceleration
1 lb = 16 oz = 4.45 newtons (N)
1 N (kg· m/s2) = 0.223 lb

Temperature
oF = 9/5 x oC + 32
oC = (oF - 32) x 5/9
Absolute Temperature, kelvin, K = oC + 273.15
0 K = -273.15 oC = -459.72 oF
Normal Body Temperature = 98.6 oF

Pressure = Force/Area
1 Pascal, Pa = 1 N/m2 = 1.45 x 10-4 lb/in2
1 bar = 105 N/m2 = 14.50 lb/in2
1 atmosphere, atm = 760 mm Hg = 76.0 cm Hg = 760 torr = 14.50 lb/in2 = 1.01325 x 105 N/m2 (or Pa)
Air pressure at sea level is approximately = 1 atm = 1 bar = 105 N/m2 (or Pa) = 14.50 lb/in2
Water pressure increases 9810 N/m2 for each meter of depth or 0.433 lb/in2 for each foot of depth

Work and Energy or Heat Work = Force x parallel distance
1 joule, J = 0.738 ft . lb = 107 ergs
1 calorie, cal = 4.18 J = 0.00442 British Thermal Units, Btu
1 foot pound, ft . lb = 1.36 J
1 Btu = 252 cal = 778 ft·lb = 1.054 x 103 J
1 electron Volt, eV = 1.602 x 10-19 J
931.5 million electron volts,MeV is equivalent to 1 atomic mass unit, u

Power = Work/time
1 horse power, hp = 550 ft·lb/s = 0.746 kilowatts, kW = 746 W
1 Watt, W = 1 J/s = 0.738 ft·lb/s = 0.00134 hp
1 Btu/hr = 0.293 W
1 kW = 1.34 hp

Radioactivity
1 curie = 3.70 x 1010 disintegrations/second = 3.70 x 1010 bequerels

SI BASE UNITSPhysical Quantity Name of UnitSymbolLengthmetermMass kilogramkgTimesecondsTemperaturekelvinKElectric currentampereALuminous intensitycandelacdAmount of substancemolemol

SI PREFIXESMACROMICROFactorPrefixSymbolFactorPrefixSymbol1018exaE10-1decid1015petaP10-2centic1012teraT10-3millim109gigaG10-6microμ106megaM10-9nanon103kilok10-12picop102hectoh10-15femtof101dekada10-18attoa

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3 years ago

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Natalie picks 40 bushels in 12 hours and Mary can pick the same amount in 11 hours. how long would it take if they worked togeth

rosijanka [135]

Answer: $5.73\ hours$ or $5\ hours\ and\ 44\ minutes$

Step-by-step explanation:

You can use the following work-rate formula:

$\frac{t}{t_A}+\frac{t}{t_B}=1$

In this case let be ${t_A}$ the time it takes for Natalie to pick 40 bushels, ${t_B}$ the time it takes for Mary to pick 40 bushels and $t$ the time it takes to pick 40 bushels if they work together.