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Leya [2.2K]
3 years ago
6

Linear Functions 3-2 additional Practice

Mathematics
1 answer:
Ainat [17]3 years ago
7 0

Answer: You gotta do your own homework sometimes :(

Step-by-step explanation: Ask the questions separately

maybe you will get better answers.

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The price of a bracelet increased from $170 to $200 on Mother's Day.
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Ariel snowboarded down a mountain that has a vertical height of 1,200 feet. She traveled a distance of 2,400 feet from the top o
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3 years ago
An increased number of colleges have been using online resources to research applicants. According to a study from last​ year, 3
Aneli [31]

Answer:

D. H0​: p ≤0.36 H1​: p>0.36

$$(Right tail test) Z_{\alpha}=Z_{0.1}=1.28155

Z_p=-0.25516

D. Reject H0. There is sufficient evidence to support the hypothesis that the proportion of admissions officers who visit an applying​ students' social networking page has increased in the past year

Step-by-step explanation:

To solve this problem, we run a hypothesis test about the population proportion.

$$Sample proportion: $\bar P=0.47\\Sample size n=100$\\Significance level \alpha=0.10$\\(Left tail test) Z_{1-\alpha}=Z_{0.90}=-1.28155$\\(Right tail test) Z_{\alpha}=Z_{0.1}=1.28155$\\(Two-tailed test) $Z_{1-\alpha/2}=Z_{0.95}=-1.64485$ and $ Z_{\alpha/2}=Z_{0.05}=1.64485\\\\

The appropriate hypothesis system for this situation is:

H_0:\pi_0=0.35\\H_a:\pi_0 > 0.35\\\\$Proportion in the null hypothesis is:\\\pi_0=0.35\\\\

$$The test statistic is $Z=\frac{(\bar P-\pi_0)\sqrt{n}}{\sqrt{\pi_0(1-\pi_0)}}\\$The calculated statistic is Z_c=\frac{(0.47-0.35)\sqrt{100}}{\sqrt{0.35(1-0.35)}}=-0.25516\\p-value = P(Z \geq Z_c)=0.01620\\\\

Since, the calculated statistic Z_c is greater than critical Z_{\alpha}, the null hypothesis should be rejected. There is enough statistical evidence to state that the proportion of admissions officers who visit an applying​ students' social networking page has increased in the past year.

5 0
3 years ago
Substitute y=-x+6 x-2y=-6
Ksenya-84 [330]
<span><span>x-4x+12=6
-3x+12=6
-3x+12-12=6-12
-3x=-6
-3x/-3=-6/-3
x=2
Plug (2) in for x in L2 and solve for y:

y=2(2)-6
y=4-6
y=-2
The solution (x,y)=(2,-2)
Check in both equations by substituting (x,y)=(2,-2) and see if it equals out:
L1) (2)-2(-2)=6
2+4=6
6=6 L1 checks out.
L2) (-2)=2(2)-6
-2=4-6
-2=-2 L2 checks out also, so we can say with confidence that the solution is right.
</span></span>
7 0
3 years ago
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