Answer:
181.99956681
Step-by-step explanation:
Mark as brainliest
Answer:
log9
Step-by-step explanation:
hello :
note : a>0 and b>0
1) log(ab) = loga+logb
2) loga^n = nloga.....n in N
log(9x^5) + 5 log (1/x) = log(9x^5) + log (1/x)^5 = log((9x^5) (1/x)^5)
= log(9x^5)/(x^5)) = log9 because : (1/x)^5 = 1/x^5
<span>A)x-y+3 is your answer
Proof:
(5 x)/4 - 8 y - x/4 + 7 y + 3
Put each term in (5 x)/4 - 8 y - x/4 + 7 y + 3 over the common denominator 4: (5 x)/4 - 8 y - x/4 + 7 y + 3 = (5 x)/4 - (32 y)/4 - (x)/4 + (28 y)/4 + 12/4:
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4
(5 x)/4 - (32 y)/4 - x/4 + (28 y)/4 + 12/4 = (5 x - 32 y - x + 28 y + 12)/4:
(5 x - 32 y - x + 28 y + 12)/4
Grouping like terms, 5 x - 32 y - x + 28 y + 12 = (28 y - 32 y) + (5 x - x) + 12:
((28 y - 32 y) + (5 x - x) + 12)/4
28 y - 32 y = -4 y:
(-4 y + (5 x - x) + 12)/4
5 x - x = 4 x:
(-4 y + 4 x + 12)/4
Factor 4 out of -4 y + 4 x + 12:
(4 (-y + x + 3))/4
(4 (-y + x + 3))/4 = 4/4×(3 + x - y) = 3 + x - y:
Answer: 3 + x - y
</span>
Answer:
78.54
Step-by-step explanation:
Hope this helps!
