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Trava [24]
3 years ago
5

The quadratic has a vertex of (10,-9) and y-intercept of (0,-4). Write an equation in vertex form. PLZ EXPLAIN!!!!

Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0
Hello there!

Knowing that the vertex form of the quadratic equation is
y=a(x-h)^2+k where (h,k) represents the vertex, and the a value represents the leading coefficient of the quadratic equation in standard form, first plug in your known values (your given coordinate point can be plugged into the x and y values, and your given vertex can be plugged into h and k):
-4=a(0-10)^2-9

Because your a value is still unknown, you can use your given values in the equation to solve for a:
-4=a(-10)^2-9
-4=100a-9
100a=5
a=1/20

Now that you have your a value, you can plug it into your vertex form as well as your vertex values to get that your equation in vertex form is:
y=1/20(x-10)^2-9
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PLEASE HELP!
Mariana [72]
-----------------------------------------------
Information Given:
-----------------------------------------------
ON = 7x - 9
LM = 6x + 4
MN = x - 7
OL = 2y - 7

-----------------------------------------------
Since it is a parallelogram:
-----------------------------------------------
ON = LM and
MN = OL

-----------------------------------------------
ON = LM:
-----------------------------------------------
7x - 9 = 6x + 4

-----------------------------------------------
Subtract 6x from both sides:
-----------------------------------------------
x - 9 = 4

-----------------------------------------------
Add 9 to both sides:
-----------------------------------------------
x = 13

-----------------------------------------------
MN = OL:
-----------------------------------------------
x - 7 = 2y - 7

-----------------------------------------------
Sub x = 13:
-----------------------------------------------
13 - 7 = 2y - 7

-----------------------------------------------
Simplify:
-----------------------------------------------
6 = 2y - 7

-----------------------------------------------
Add 7 on both sides:
-----------------------------------------------
13 = 2y

-----------------------------------------------
Divide by 2:
-----------------------------------------------
y = 13/2

-----------------------------------------------
Answer: x = 13, y = 13/2 (Answer D)
-----------------------------------------------


6 0
3 years ago
Assume that θ is a positive acute angle.<br><br> Given: sin θ =28/53<br> Find: sin2θ
antiseptic1488 [7]

Answer:

725 - 360 = 365

365 - 360 = 5

The acute angle is 5 degrees.

sin2θ = sin(2*5) = sin(10) = 0.1736

Step-by-step explanation:

3 0
2 years ago
HELP ASAP!! 100 POINTS!!<br><br> describe how you would plot the point (-4, 3)
fredd [130]

Answer:

Hi!

First you would start at -4 on the x-axis, then you would move up 3 spaces and put your point there.

The x-axis is the horizontal line, and the y-axis is the vertical line.

I hope this helps you!

6 0
3 years ago
Read 2 more answers
PLEASE HELP! Sakura's house is at an elevation between 113 m and 120 m above sea level. Her friend Ted lives about 15 m below he
EastWind [94]

Answer:

98 and 105

Step-by-step explanation:

4 0
3 years ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
2 years ago
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