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3 years ago

HELP meeeeee please

Mathematics

1 answer:

Rufina [12.5K]3 years ago

8 0

Answer: a = 23, b = 21, c = 136

Step-by-step explanation:

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The ground temperature at an airport is 10 °C. The temperature decreases by 5.4 °C for every increase of 1 kilometer above the g

Paraphin [41]

The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Given that,

The ground temperature at the airport is 10 °C.
The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.

Based on the above information, the temperature outside should be

The decrease in the temperature should be

= 5.4×5

= 27°C

Now the final temperature is

= 10 - 27

= -17°C

Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Learn more: brainly.com/question/20459283

5 0

3 years ago

What is the nth term of 12 10 8 6 4 ?

tino4ka555 [31]

Answer:

-4

Step-by-step explanation:

The difference from each number is 2 so u keep subtracting 2 from each term until u get to the nth term. For ex: 12-2=10, 10-2=8, 8-2=6...

7 0

4 years ago

Una sustancia se encuentra en 15°c pero a partir de comienzo de un experimento su temperatura disminuye de manera uniforme a raz

bija089 [108]

Answer:

1= -15 °C

2= 7 minutos y medio

Step-by-step explanation:

1= colo la temperatura va bajando 2 grados cada minuto lo único que hay que hacer es restarle 30 °C a 15 y nos da -15 ° C

2= Solo divides 15 entre 2 y ya.

6 0

3 years ago

The area of a rectangular piece of plastic is 10 square millimeters. The perimeter is 22 millimeters. What are the dimensions of

Serhud [2]

2789 dimensions because it’s simple u multiple them

4 0

3 years ago

Make a histogram, using a bin width of ten, to display the bowling scores for these 31 players: 87, 104, 79, 94, 117, 82, 72, 11

slavikrds [6]

Step-by-step explanation:

Using R, I used the following code to create a histogram:

bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,

103, 112, 97, 73, 85, 91, 86, 102, 99, 106, 84, 98, 83, 81, 96, 92)

data.frame(bowling.scores)

ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +

xlim(c(70, 120)) +

scale_y_continuous(breaks = seq(0, 10, by=1), "Frequency") +

geom_histogram(breaks=seq(70, 120, by=10), color="black", fill="grey60") +

labs(title="Histogram of Bowling Scores", x="Bowling Scores", y="Frequency")

7 0

3 years ago