the equation that we can solve using the given system of equations is:
3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0
<h3>Which equation can be solved using the given system of equations?</h3>
Here we have the system of equations:
y = 3x^5 - 5x^3 + 2x^2 - 10x + 4
y = 4x^4 + 6x^3 - 11
Notice that both x and y should represent the same thing in both equations, then we could write:
3x^5 - 5x^3 + 2x^2 - 10x + 4 = y = 4x^4 + 6x^3 - 11
If we remove the middle part, we get:
3x^5 - 5x^3 + 2x^2 - 10x + 4 = 4x^4 + 6x^3 - 11
Now, this is an equation that only depends on x.
We can simplify it to get:
3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0
That is the equation that we can solve using the given system of equations.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Answer:
Find the question mark using the model I've provided and that'll be the answer!
(-5x^5)(a) = 25x^7 + 100x^5
<u>+5x^5 +5x^5</u>
a = 25x^7
100-15=85
Therefore 0.85 is the multiplier
So 243.00 times by 0.85 = 206.55
He won about 25% because 6/12 would be 1/2 and 3 is 1/2 of 6 or a 1/4 so 25%