Answer:
A sample size greater than 30
Step-by-step explanation: The central limit theorem proffers the conditions necessary to obtain a normal or bell shaped distribution. It defines normal distribution in terms of mean, standard deviation and sample size. The sample size is a very important factor in determining the shape of a distribution.
Thus with a population having mean and standard deviation stated, in other to make use of or assume normal distribution, the sample size must be large. According tho the central limit theorem, a size of greater than 30 is deemed to be large enough. As the Same size increases, the sample mean converges to the value of the population mean.
Answer:
its 12.5
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) (xy+ 9y + 2) and (xy – 3)
Each term of second expression will be multiplied by first bracket.
xy(xy+9y+2) -3(xy+9y+2)
x²y²+9xy²+2xy-3xy-27y-6
x²y²+9xy²-xy-27y-6
2) (2xy + x + y) and (3xy2 – y)
3xy²(2xy+x+y) -y(2xy+x+y)
6x²y³+3x²y²+3xy³-2xy²-xy-y²
6x²y³ – 2xy² + 3x²y² – xy + 3xy³ – y²
3) (x – y) and (x + 3y)
x(x-y) +3y(x-y)
x²-xy+3xy-3y²
x²+2xy-3y²
4) (xy + 3x + 2) and (xy – 9)
xy(xy + 3x + 2) -9(xy + 3x + 2)
x²y²+3x²y+2xy-9xy-27x-18
x²y²+3x²y-7xy-27x-18
5) (x2 + 3xy – 2) and (xy + 3)
xy(x2 + 3xy – 2) +3(x2 + 3xy – 2)
x³y+3x²y²-2xy+3x²+9xy-6
x³y+3x²+3x²y²+7xy-6
6) (x + 3y) and (x – 3y)
x(x + 3y) -3y(x + 3y)
x²+3xy-3xy-9y²
x²-9y² ....
Answer:
a.) Expected value on earning points= 21
b.) Expected value on earnings for composites = -1
Step-by-step explanation:
Expected value = [(6*1 + 6*2 + 6*3 + 6*4 + 6*5 + 6*6 ) ]* (1/6) = 6*(7)/2 = 21
b.) how many composite numbers from 1 to 6
4 and 6
so...
Expected Value of earning = [(-6*1 - 6*2 - 6*3 + 6*4 - 6*5 + 6*6 ) ]* (1/6) =
-1 - 2 - 3 + 4 - 5 + 6 = -1
