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Marianna [84]
3 years ago
15

3 • 4/12 to the simplest form

Mathematics
1 answer:
beks73 [17]3 years ago
3 0
9 because you would turn 4 12 in simplest form the times it by 3

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Please answer the question, i took a picture of it.
PIT_PIT [208]

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640 is the Answer

Step-by-step explanation:

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Figure B is the image of Figure A when reflected across line ℓ. Are Figure A and Figure B congruent
soldi70 [24.7K]

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If they are reflection. I think they are congruent

Step-by-step explanation:

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3 years ago
What is 6.23 million written in scientific notation?
taurus [48]

Answer:

6.23*10^6

Step-by-step explanation:

We first write the answer in full notation 6,230,000.

Then we count how many decimal places it takes before we have one leading digit. Since it is six, we move the decimal place and write 6.23*10^6

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2 years ago
-24 = -3w +21 what is w?
yuradex [85]

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Step-by-step explanation:

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3 years ago
Suppose that F is an inverse square force field below, where c is a constant.
Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

a)

First of all we have,

F(r) = \frac{cr}{|r|^{3} }

and,

r = xi+yj+zk

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

f(r) = - c /|r|

That is,

\nabla f = F

For this case F is a conservative field and the line integral is independent of the path. Thus, defining  P_{1} = (x_{1}, y_{1}, z_{1}) and P_{2} = (x_{2}, y_{2}, z_{2}) . So the amount of work on the movement of the object from P1 to P2 is,

W=\int\limits_c  {F} \, dr

W= f(P_{1}-P_{2})

W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}

W= c(\frac{1}{d1}-\frac{1}{d2}  )

2) The gravitational force field is given by,

F(r) =-\frac{mMGr}{ |r|^3}

The maximum distance from the earth to the sun is 1.52*10 ^ 8 km and the minimum distance is 1.47*10 ^ 8km. The mass values of the bodies are given by m = 5.97*10 ^ {24}kg, M = 1.99 *19 ^ {30}kg and the constant G is 6.67 * 10 ^{ -11 } \frac{Nm ^ 2}{kg^2}

In this way we raise the problem like this,

c= -mMG

W= -mMG (\frac{1}{1.52*10 ^ 8} -\frac{1}{1.47*10 ^ 8} )

W= -(5.95*10^{24})(1.99*10^{30})(6.67*10^{-11})(-2.2377*10^{-10})

W \approx 1.77*10^{35}}J

5 0
3 years ago
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