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Usimov [2.4K]
3 years ago
8

What information can be used to compare linear relationships?

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
8 0

Sample Response:

Linear relationships can be compared using their initial values, or y-intercepts, and their rates of change, or slopes. Initial values can tell you which relationship started with a greater value. Comparing slopes can tell you which relationship is rising or falling faster.

anygoal [31]3 years ago
7 0
<span>Line graphs are used to display data or information that changes continuously over time. hope that helped</span>
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∆ABC transforms to produce ∆A'B'C'. Which transformation did NOT take place?
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a

Step-by-step explanation:

hhhhihhubtbyvyvyvtvtvtvtvrttjjjjjj

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3 years ago
Great Granola makes a trail mix consisting of peanuts, cashews, raisins, and dried cranberries. The trail mix sells for $3.50, a
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A C D

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3 years ago
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Write an equation for each translation of y=|x| 15.5 units down
Korolek [52]
<span> y+15.5=|x|
</span><span> y=|x|-15.5 </span> 
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3 years ago
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y = x2 - 6x - 8 Complete the square in the quadratic equation in order to write the equation in vertex form.
Airida [17]

Answer:

y = (x-3)^2 - 17

Step-by-step explanation:

To complete the square, take the middle term bx and divide it in two. Then take the square.

x^2 - 6x - 8 has bx = -6x. Take -6/2 = -3. Square -3^2 = 9.

Now to finish completing the square add 9 and subtract 9 from one side.

y = x^2 - 6x - 8

y = (x^2 - 6x +9) -9 - 8

y = (x-3)^2 - 17

8 0
3 years ago
Find the values of x and y
zhuklara [117]

You can use a tangent:

tangent=\dfrac{opposite}{adjacent}

We have opposite = 17 and adjacent = x.

\tan30^o=\dfrac{\sqrt3}{3}

substitute:

\dfrac{17}{x}=\dfrac{\sqrt3}{3}       cross multiply

x\sqrt3=(3)(17)     multiply both sides by √3

x(\sqrt3)(\sqrt3)=51\sqrt3

3x=51\sqrt3      divide both sides by 3

x=17\sqrt3

Use the Pythagorean theorem:

y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34

-------------------------------------------------------------------------------------------------

Other method.

30^o-60^o-90^o triangle.

The sides are in the ratio 1:2:\sqrt3\to17:y:x

Therefore

17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3

 


4 0
3 years ago
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