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ivanzaharov [21]
3 years ago
12

Someone please help me

Mathematics
2 answers:
hjlf3 years ago
5 0
A.
Point A is (2,7)
Point B is (-4,6)
Point D is (-3,-3)
Point E is (0,2)
Point F is (7,-7)

B.
From the middle, go 4 to the right and then 7 down, then draw a dot there and label it G.

C.
From the middle again, go 6 to the left then 6 down, draw a dot there and label it H.
Arlecino [84]3 years ago
4 0

Answer

hope this helps =)

Step-by-step explanation:

a (2,7)

b (-4,6)

d (-3,-3)

e (0,2)

f (7,-5)  

sorry for the bad quality of the photo but i hope you see it well

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In Exercise sketch the graph of the function.<br> f(x) = ex + 3
Tju [1.3M]

Answer:

f(x) = e^x + 3

Step-by-step explanation:

We are given the following function in the question:

f(x) = e^x + 3

We have to graph this function.

Properties of given function are:

  • e is a constant and have a value of e = 2.718281828....
  • The function does not pass through origin
  • At x = 0, f(x) = 4
  • The domain for the given function is all real numbers.
  • The range of the given function is (3, \infty)

The attached image shows the graph for given function.

5 0
3 years ago
Shane covered a 10 ft. By 14 ft. Wall with wall paper. To match the pattern, he bought 20% extra. Each role of paper covers 30 f
kotykmax [81]
((There has been a malfunction or this users account may have been deleted))
5 0
3 years ago
1 , 3 , 6 , 10 , 15
Bas_tet [7]

First difference,

\Delta_{1} =  a_{2} - a_{1} = 3 - 1 = 2 = 1  + 1

Second difference,

\Delta_{2} =  a_{3} - a_{2} = 6 - 3 = 3 = 2 + 1

Third difference,

\Delta_{3} =  a_{4} - a_{3} = 10 - 6 = 4  = 3 + 1

And so on.

Assuming the pattern holds on, we see that

i-th difference,

\Delta_{i} =  a_{i + 1} - a_{i} = i + 1

\implies a_{i + 1} = a_{i}  +  i +  1

Then, nth term is,

\implies a_{n} = a_{n - 1} + n

= a_{n - 2}+ (n  + (n - 1))

= a_{n - 3} + (n + (n - 1) +(n - 2))

= a_{n - (n - 1)} + \sum \limits^{n - 2}_{k = 0}(n - k)

= a_1 + \sum \limits^{n - 2}_{k = 0}n-  \sum \limits^{n - 2}_{k = 0}k

= a_1 +n(n -2 + 1 )-  \frac{1}{2} (n - 2)(n - 1)

= a_1 +n(n -1 )-  \frac{1}{2} (n - 2)(n - 1)

= a_1 +(n -1 )(n-  \frac{1}{2} (n - 2))

= a_1 + \frac{1}{2} (n -1 )(2n- n  +  2)

= a_1 + \frac{1}{2} (n -1 )(n  +  2)

\implies a_{n} = 1 + \frac{1}{2} (n -1 )(n  +  2)

Now, the 21st term in the sequence is,

\implies a_{21} = 1 + \frac{1}{2} (21 -1 )(21  +  2)

= 1 + \frac{1}{2}  \times 20 \times 23

= 231

4 0
3 years ago
I don't understand the math homework I need to do tonight please help
SpyIntel [72]
3 to the -2 power is basically 3x-3, which is -9, and -5 to the -3 power is (-5)(-5)(-5) which is equal to -125. hope that helped you out, bud!
4 0
4 years ago
How do you do Multiplication
icang [17]

Answer:

Write the larger number above the smaller number. ...

Multiply the number in the ones place of the bottom number by the number in the ones place of the top number. ...

Multiply the number in the ones place of the bottom number by the number in the tens place of the top

4 0
4 years ago
Read 2 more answers
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