Answer:
The correct answer is - 2n = 41 chromosomes.
Explanation:
It is given that the cat has a diploid chromosome number of 38 while the rabbit has a diploid number of 44 chromosomes and if they form a hybrid then their expected chromosome number in somatic cells would be -
Cat (2n=38) produces haploid gametes with 19 chromosomes (n-19).
Rabbit (2n=44) produces haploid gametes with 22 chromosomes(n=22)
19+22= 41 chromosomes in the particular hybrid as half number of chromosomes come from each parent.
Eukaryotic cells have a nucleus where as prokaryotic cells do not.
Answer:
50%
Explanation:
According to the given information, the woman has normal BRCA alleles while the man carries one copy of the mutated BRCA allele (BRCA1). A diploid organism such as human beings can have two BRCA alleles. A child gets one BRCA allele from the mother and the other from the father.
The child of the couple would get one normal allele from the woman. However, with respect to the BRCA allele, the man would form two types of gametes in equal proportion. The 50% of his gametes would have the mutated BRCA1 allele while the rest 50% would carry the normal BRCA allele. Therefore, the man can transmit either normal or mutated BRCA allele to the child. So, there are 50% chances for the child to get the mutated allele.
Answer:
Scientific method is not developed in the 1800s
Cells because all living organisms have cells
