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Darina [25.2K]
4 years ago
9

25 POINTS!

Mathematics
1 answer:
bekas [8.4K]4 years ago
6 0

Answer:

y-5=4(x+3)

Step-by-step explanation:

y-y1=m(x-x1)

y-5=4(x-(-3))

y-5=4(x+3)

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Diego has 27 ounces of juice he pours equal amounts for each of his three friends and has 6 ounces left for him select the equat
Orlov [11]

Answer:

27÷4=6.75

Step-by-step explanation:

5 0
4 years ago
For an arithmetic sequence,first term is 2 and the common difference is 3 find the sum of the first 11
romanna [79]

Answer:

35

Step-by-step explanation:

by adding three to the next number each time, the answer is 35

6 0
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Help, I am unsure about what to do exactly
noname [10]
You plug in number for number getting 194.8 which is equal to 2931
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3 years ago
What is the amplitude of the function?
bazaltina [42]

Answer:

Step-by-step explanation:

The amplitude is half of the range.

a=(maximum-minimum)/2, in this case

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6 0
3 years ago
There are 20 machines in a factory. 7 of the machines are defective.
adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0
3 years ago
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