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LiRa [457]
3 years ago
10

I need help with this! I'll mark Brainliest if it's correct.

Mathematics
1 answer:
Sauron [17]3 years ago
5 0
Answers:
Coordinates of H are: (a,a)
The slope of segment GJ is: -1
The product of the slopes of the diagonals is: -1

-------------------------------------------------------

Explanation:

Point J has an x coordinate of x = a
Point G has a y coordinate of y = a
So point H has the coordinates (x,y) = (a,a)
We simply move straight up from point J to get to H. At the same time, we move horizontally across to go from G to H. This is why H has half the coordinates from each J and G

----------

As for the slope of GJ, we use the slope formula
m = (y2-y1)/(x2-x1)
m = (0-a)/(a-0)
m = -a/a
m = -1
So that shows why the slope of GJ is -1

Multiplying the slope of KH (1) and the slope of GJ (-1), we get
1 times -1 = -1
The product being -1 shows the diagonals KH and GJ are perpendicular. They form a 90 degree angle. 
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Answer:

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Step-by-step explanation:

5 0
2 years ago
Can anyone help with this
mestny [16]
The sum of the interior angles of a triangle is always 180 degrees.  Thus,
the sum of 31, x+4 and 3x+9 must be 180.

31 + x + 4 + 3x + 9 = 180,     or    44 + 4x = 180


While it's not necessary, y ou could reduce this equation before solving for x:

11 + x = 45.             Then x = 34 degrees.

The three angles are then:

31
34+4 = 38
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Check:  show that 31+38+111 = 180 (degrees)
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The first terms of a geometric sequence are as follows.
Flauer [41]

The fourth and fifth term of this sequence is -30 and -10 respectively.

Data;

  • first term (a) = -810
  • common difference (r) = ?

<h3>Common Difference</h3>

The common difference in a geometric progression is the ratio between two successive terms.

Let's find the common difference in this sequence

r = \frac{-270}{-810} \\r = \frac{1}{3}

The nth term of a geometric sequence is given as

T_n = ar^n^-^1\\

The next two terms of this sequence will be 4th and 5th term.

The fourth term of this sequence is

T_4 = ar^4^-^1\\T_4 = -810 * (\frac{1}{3})^3\\ T_4 = -810 * \frac{1}{27}\\ T_4 = -30

The fifth term of this sequence is

T_5 = ar^5^-^1\\T_5 = -810 * (\frac{1}{3})^4\\T_5 = -810 * \frac{1}{81} \\T_5 = -10

The fourth and fifth term of this sequence is -30 and -10 respectively.

Learn more on geometric progression here;

brainly.com/question/12006112

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