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vlada-n [284]
3 years ago
13

A mother seal is fed 5 fish for every 2 fish for its baby. If mother is fed 8 fish how many does the baby get

Mathematics
1 answer:
iogann1982 [59]3 years ago
7 0
5/2 = 8/x

5x = 16

x = 16/5

x = 3.2 or 3 1/5 fish
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Y=(2x-3)^5(2-x^4)^3 differentiate the function please
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3 years ago
Anyone know of some good books to read?
goblinko [34]
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4 0
2 years ago
Read 2 more answers
Write an equation of the line that passes through (3,1) and (0,10)
tangare [24]

Step-by-step explanation:

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4 0
2 years ago
What is the sum of the first 51 consecutive odd positive integers?
Angelina_Jolie [31]
We call:

a_{n} as the set of <span>the first 51 consecutive odd positive integers, so:

</span>a_{n} = \{1, 3, 5, 7, 9...\}

Where:
a_{1} = 1
a_{2} = 3
a_{3} = 5
a_{4} = 7
a_{5} = 9
<span>and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

</span>a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}
<span>
Then:

</span>a_{n} = a_{1} + (n-1)d
<span>
So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

</span>S_{k} = ( \frac{a_{1} +  a_{k}}{2}  ).k
<span>
Therefore, we need to find:
</span>a_{k} =  a_{51}  

Given that a_{1} = 1, then:

a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1

Thus:
a_{k} = a_{51} = 2(51)-1 = 101

Lastly:

S_{51} = ( \frac{1 + 101}{2} ).51 = 2601 

4 0
3 years ago
Josh mows grass to earn extra money. He charges $25.00 for each lawn. He mows at least 5 yards each week; but not more than 20 y
aleksklad [387]

Answer:

Let

x = number of yards mowed

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Which is the same as

125  ≤  f(x)  ≤ 500

(Range of the function)

Domain   5 ≤  x  ≤ 20

Range     125  ≤  f(x)  ≤ 500

3 0
3 years ago
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