<em></em> $The\ function\ is\ odd\ if\ f(-x)=-f(x)\\\\We\ know:\\\sin x;\ \tan x\ and\ \cot x\ are\ odds.\\\cos x\ is\ even\ /\cos(-x)=\cos x/\\--------------------\\\\A.\ y=\sec x\\\\\sec(-x)=\dfrac{1}{\cos(-x)}=\dfrac{1}{\cos x}=\sec x-\fbox {NO}\\\\B.\ y=\sin x-\fbox{YES}\\\\C.\ y=\cot x\\\\\cot(-x)=\dfrac{\cos(-x)}{\sin(-x)}=\dfrac{\cos x}{-\sin x}=-\dfrac{\cos x}{\sin x}=-\cot x-\fbox{YES}\\\\D.\ y=\csc x\\\\\csc(-x)=\dfrac{1}{\sin(-x)}=\dfrac{1}{-\sin x}=-\dfrac{1}{\sin x}=-\csc x-\fbox{YES}$

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3 years ago

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Answer:

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5 0

2 years ago

Can anyone solve this? Thanks!​

Can anyone solve this? Thanks!