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iren [92.7K]
3 years ago
5

="latex-formula">
Mathematics
1 answer:
ss7ja [257]3 years ago
3 0
The first step for solving this expression is to convert the decimal number into a fraction.
6\sqrt{ \frac{2}{5} }
Remember that in order to take a root of a fraction,, you must take the root of the numerator and denominator separately. This will look like the following:
6 × \frac{ \sqrt{2} }{ \sqrt{5} }
Now calculate the product.
\frac{6 \sqrt{2}}{ \sqrt{5} }
Lastly,, rationalize the denominator to find your final answer.
\frac{6 \sqrt{10} }{5}
Let me know if you have any further questions.
:)
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the sides of a square each have a length of 11x inches write an expression for the perimeter of the square in inches
notsponge [240]

Answer:

  • P = 44x

Step-by-step explanation:

<u>Given </u>

  • a = 11x

<u>Perimeter of a square is:</u>

  • P = 4a

<u>Substitute the value:</u>

  • P = 4(11x) = 44x
4 0
3 years ago
For 0 ≤ θ &lt; 2 π what are the solutions to sin^2(θ) =2sin^2(θ/2)
gregori [183]

Recall the half-angle identity for sine,

sin²(x/2) = (1 - cos(x))/2

Then the given equation is identical to

sin²(θ) = 1 - cos(θ)

Also recall the Pythagorean identity,

sin²(θ) + cos²(θ) = 1

Then we rewrite the equation as

1 - cos²(θ) = 1 - cos(θ)

Factoring the left side, we have

(1 - cos(θ)) (1 + cos(θ)) = 1 - cos(θ)

and so

(1 - cos(θ)) (1 + cos(θ)) - (1 - cos(θ)) = 0

and we factor this further as

(1 - cos(θ)) (1 + cos(θ) - 1) = 0

which gives

cos(θ) (1 - cos(θ)) = 0

Then either

cos(θ) = 0   or   1 - cos(θ) = 0

cos(θ) = 0   or   cos(θ) = 1

[θ = arccos(0) + 2nπ   or   θ = -arccos(0) + 2nπ]

…   or   [θ = arccos(1) + 2nπ   or   θ = -arccos(1) + 2nπ]

(where n is any integer)

[θ = π/2 + 2nπ   or   θ = -π/2 + 2nπ]   or   [θ = 0 + 2nπ]

In the interval 0 ≤ θ < 2π, we get three solutions:

• first solution set with n = 0   ⇒   θ = π/2

• second solution set with n = 1   ⇒   θ = 3π/2

• third solution set with n = 0   ⇒   θ = 0

So, the first choice is correct.

6 0
3 years ago
A high school sports team is ordering sports drinks online from a company. The price of sports drinks varies, based on the numbe
Elena-2011 [213]

The amount of drinks is a linear function of the number of drinks. The maximum amount that can be purchased is 100 soft drinks.

Let

y \to amount of drinks

x \to number of drinks

For drinks not more than 50

y = 10 + 0.8x

For drinks more than 50.

y = 15 + 0.7x

For a purchase of $85, it means that:

y = 85

So, we solve for x in both equations.

y = 10 + 0.8x

85 = 10 + 0.8x

Collect like terms

0.8x = 85-10

0.8x = 75

Divide through by 0.8

x = 93.75

x = 94 --- approximated

y = 15 + 0.7x

85 =15 + 0.7x

Collect like terms

0.7x = 85 - 15

0.7x = 70

Divide by 0.7

x = 100

By comparing both values:

x = 100

x = 94

100 > 94

Hence, the maximum amount that can be purchased is 100

Read more about functions at:

brainly.com/question/20286983

5 0
3 years ago
Read 2 more answers
Pls answer these 2 questions show your work
salantis [7]
Multiply 64% (0.64) x 75 =48 tiles
Multiply 85% (0.85) x 40 = 34 emails
4 0
3 years ago
what is the quotient when x3 − 5x2 2x 5 is divided by x − 2? x2 − 3x − 4 x2 − 7x 16 x2 − 3x − 4 − 3 over the quantity of x minus
nekit [7.7K]
<span><u><em>The correct answer is: </em></u>
x</span>²<span>-3x-4 -</span>\frac{3}{x-2}<span>.

<u><em>Explanation</em></u><span><u><em>: </em></u>
To divide these polynomials, the dividend, x</span></span>³<span><span>-5x</span></span>²<span><span>+2x+5, goes under the box, and the divisor, x-2, goes outside of the box.

We first want to find what we multiply x by to make x</span></span>³<span><span>; x*x</span></span>²<span><span>=x</span></span>³<span><span>, so we write x</span></span>²<span><span> over -5x</span></span>²<span><span> in the box.
 
<u>Now we multiply our divisor, x-2, by x</u></span></span><u>²</u><span><span><u>: </u>
x*x</span></span>²<span><span>=x</span></span>³<span><span>
-2*x</span></span>²<span><span>=-2x</span></span>²<span><span>.

This goes under x</span></span>³<span><span>-5x</span></span>²<span><span> in the box.

<u>Now we subtract: </u>
(x</span></span>³<span><span>-5x</span></span>²<span><span>)-(x</span></span>³<span><span>-2x</span></span>²<span><span>)=-3x</span></span>²<span><span>.

This goes below the 2x</span></span>²<span><span> we wrote, and we bring down 2x.

Now we see what we multiply x by to make -3x</span></span>²<span><span>;
x*-3x=-3x</span></span>²<span><span>, so we write -3x beside x</span></span>²<span><span> in the quotient (at the top).

<u>We multiply our divisor, x-2, by -3x: </u>
 x*-3x=-3x</span></span>²
<span><span>-2*-3x=6x.

We write -3x</span></span>²<span><span>+6x under our -3x</span></span>²<span><span>+2x and <u>subtract</u>:
(-3x</span></span>²<span><span>+2x)-(-3x</span></span>²<span><span>+6x)=-4x.

Write this below 6x. Bring down +5.

Now we see what we multiply x by to make -4x;
x*-4=-4x, so write -4 beside -3x in the quotient.

<u>Multiply our divisor, x-2, by -4: </u>
x*-4=-4x;
-2*-4=8;

write -4x+8 below -4x+5 and <u>subtract:</u>
(-4x+5)-(-4x+8)=-3.

This gives us the quotient x</span></span>²<span><span>-3x-4 with a remainder of -3, so we write our full answer as x</span></span>²<span><span>-3x-4-(3/x-2).</span></span>
3 0
4 years ago
Read 2 more answers
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