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3 years ago

Write the function y = 3(x - 1)2 + 2 in standard form.

Mathematics

1 answer:

cestrela7 [59]3 years ago

7 0

3 x 2 = 6

6(x-1) = 6x - 6

6x - 6 + 2

6x -4

hope this helps

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URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

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3 years ago

HiCan you please state the Pythagorean TheoremVerbally and algebraically

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Pythagorean Theorem<h2>Verbally:</h2>

Let's say a and b are the legs, and c is the hypotenuse. Then, algebraically, the theorem is,

$a^2+b^2=c^2$

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2 years ago

Identify the center and radius of the circle given by the equation (x+2)^2+(y-5)^2=16

Andreyy89

Answer:

Center=(0,2) Radius=(4)

Step-by-step explanation:

give me 5 star and thank me plz

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Given a possible triangle ABC with a=5, b=11, and A=23 degrees, find a possible value for angle b. Round to the nearest tenth.

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<span>b. Round to the nearest tenth. please mark brainly</span>

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4 years ago

Substitute ×=3in the following equation to find y<br>5y - 2x=9

Alexxx [7]

Answer:

y=3

Step-by-step explanation:

5y-2(3)=9

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