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yuradex [85]
2 years ago
14

Help!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
torisob [31]2 years ago
6 0

Answer:

53

Step-by-step explanation:

\frac{sin(56)}{78.6}  =  \frac{sin(90)}{ab}  \\  \\ absin(56) = sin(90) \times 78.6 \\  \\ ab =  \frac{sin(90) \times 78.6}{sin(56)}  \\ ab = 94.8 \\  \\  {x}^{2}   +  {78.6}^{2}  =  {94.8}^{2}  \\  {x}^{2}  =  {94.8}^{2}  -  {78.6}^{2}  \\  {x}^{2}  = 8987.04 - 6177.96 \\  {x}^{2}  = 2809.08 \\ x =  \sqrt{2809.08}  \\ x = 53

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In a 3-digit number, the hundreds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the s
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The mentioned number in the exercise is:

  • <u>362</u>

Step-by-step explanation:

To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.

If:

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  • y = tens digit
  • z = ones digit

We can write:

  1. x = z + 1 (the hundreds digit is one more than the ones digit).
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Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:

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  • 2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
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And we'll use the second equation to obtain the value of y (the tens digit):

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  • y = 2(3)
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Organizing the digits, we obtain the number:

  • Number = xyz
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As you can see, <em><u>the obtained number is 362</u></em>.

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