3 years ago

Solve u^2= -25, where u is a real number.

Mathematics

1 answer:

Tatiana [17]3 years ago

8 0

the answer is ±5i :)

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Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

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3 years ago

ASAP please i need help

Alla [95]

Answer:

1 hr 20 min.

Step-by-step explanation:

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How many 5-digit numbers can be formed if each one uses all the digits 0,1,2,3,4

Anettt [7]

Answer:

{0, 1, 2, 3, 4} --> 96 5-digit numbers possible with this set.

Step-by-step explanation:

i dunno, i kinda just searched it up

link: https://gmatclub.com/forum/how-many-five-digit-numbers-can-be-formed-using-digits-91597.html#:~:text=If%200%20is%20included%3A,numbers%20possible%20with%20this%20set.

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3/10 for green Percent: 30% Decimal:0.3
2/10 for red Percent: 20% Decimal: 0.2

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Amber shared her photo with 3 people. They continued to share it, so the number of shares increases every day as shown by the fu

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THAT THEY ARE THE SAME BUT THEN AGAIN YOU MAKE THE CHANGES YOURSELF.

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