Answer:
if x equals 2 and y equals negative 6 then the answer is....
A. -1
Step-by-step explanation:
I think it’s width but I’m not sure
Answer: A) none of the equations are identities
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Part 1
Plug in theta = 0
sin(theta+pi/2) - cos(theta+pi/6) = 2*cos(theta) - sin(theta)
sin(0+pi/2) - cos(0+pi/6) = 2*cos(0) - sin(0)
1 - sqrt(3)/2 = 2*1 - 0
0.13 = 2
which is a false equation
So we do not have an identity in equation 1.
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Part 2
Plug in theta = 0
sin(theta+pi/6) + cos(theta+pi/3) = (sqrt(2)/3)*sin(theta) + 2*cos(theta)
sin(0+pi/6) + cos(0+pi/3) = (sqrt(2)/3)*sin(0) + 2*cos(0)
1/2 + 1/2 = 0 + 2
1 = 2
which is also false
This is not an identity either.
Answer:
3,3/2
Step-by-step explanation:
let 10,-6 be x1, y1
-4,-9 be x2, y2
(x1+x2)/2 , (y1+y2)/2
(10-4)/2 , (-6+9)/2
6/2 , 3/2
3 , 3/2
