3 years ago

Anyone? /: please help!!

Mathematics

1 answer:

NeTakaya3 years ago

5 0

The answer is Side RQ corresponds to side QQ'. 100% sure and please feel free to ask more.

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Nathan is building a toolshed with a rectangular floor. The area of a rectangle is given by the formula l⋅w, where l represents

morpeh [17]

Answer:

L=7 and W=7 will have a larger floor

Step-by-step explanation:

8*6=48

7*7=49

49>48

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3 years ago

Three vertices of a rectagle are shown in the grid. What are the coordinates of ththe missing

zmey [24]

Answer:

where is the grid?????................

7 0

3 years ago

Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is <span>D. 12xy^2
</span>
$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

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3 years ago

Which of the following grid correctly graphs the points A (3,1) and C (1,3)

musickatia [10]

Answer:

its the top right

Step-by-step explanation:

x before y

4 0

3 years ago

Read 2 more answers

Evaluate x+x-x for x=4

sattari [20]

Answer:

4+4-4=4 im not sure actually D:

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4 years ago