100y+x=230
150y+x=320
Y being the price per kilogram of steel bar, x being the added delivery fee.
If you were to solve the equaltion it would go x=230-100y by changing the first equation around the replacing that for the x int he second group, so you would get 150y+230-100y=320 or 50y=90 So Y=9/5dollars per kilogram. Or $1.8per kilogram, the delivery fee being $50
Answer:
50
Step-by-step explanation:
Answer:
Step-by-step explanation:
If you want to factor this, you have to use the quadratic formula to do so.
![x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%2B%2F-%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D)
For us, it looks like this:
![x=\frac{-3+/-\sqrt{(-3)^2-4(5)(4)} }{2(5)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-3%2B%2F-%5Csqrt%7B%28-3%29%5E2-4%285%29%284%29%7D%20%7D%7B2%285%29%7D)
which simplifies to
![x=\frac{-3+/-\sqrt{-71} }{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-3%2B%2F-%5Csqrt%7B-71%7D%20%7D%7B10%7D)
Since it breaks every mathematical rule to have a negative number under an even index radical, we have to deal with that using the imaginary "i". You should know at this point that ![i^2=-1](https://tex.z-dn.net/?f=i%5E2%3D-1)
so we will do a rewrite on that equation above:
![x=\frac{-3+/-\sqrt{i^2*71} }{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-3%2B%2F-%5Csqrt%7Bi%5E2%2A71%7D%20%7D%7B10%7D)
which simplifies further to
![x=\frac{-3+/-i\sqrt{71} }{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-3%2B%2F-i%5Csqrt%7B71%7D%20%7D%7B10%7D)
This is the answer but we can separate it into its proper standard form which is
and ![x=-\frac{3}{10}-\frac{\sqrt{71} }{10}i](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B3%7D%7B10%7D-%5Cfrac%7B%5Csqrt%7B71%7D%20%7D%7B10%7Di)
0.999998 meters are approximately in 39.37 metters
Change into an improper fraction. 2247/10 then divide. So, 224.7. Or since you know 7/10 is 0.7 just add 224