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3 years ago

11

The given figure shows a circle with centre at o and angel AOB=90degree. If the radius the circle is 40c.m and pie=3.14; calcula

te the area of the unshaded portion of the circle

1 answer:

GREYUIT [131]3 years ago

3 0

A circle is 360° in total, so the unsheded part should be 270 degrees. to calculate arc area, just calculate the circle area x 270/360, so here it'll be 40 square x pi x 270/360 so the answer is 3768 cm2

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Vesna [10]

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add -5 to both sides
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3 years ago

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Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

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According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

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Cancel out common factors.

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By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

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(b)

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The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

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Step-by-step explanation:

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Step-by-step explanation:

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