A town recreation hall needs to build a ramp. The height of the ramp must be 2 ft. The ramp will start 6 ft from the door. To th
1 answer:
Answer:
6.32 feets
Step-by-step explanation:
Given that:
Height of ramp = 2 feets
Length of base = 6 feets
Length of ramp = l
Using Pythagoras rule :
Hypotenus = sqrt(opposite² + adjacent²)
Length of ramp = sqrt(height of ramp² + length of base²)
l = sqrt(2² + 6²)
l = sqrt(4 + 36)
l = sqrt(40)
l = 6.3245
Length of ramp = 6.32 feets
You might be interested in
Given:
The system of equations that represent the constraints for the given situation is
To find:
The solution of given system of equations.
Solution:
We have,
...(i)
...(ii)
Multiply equation (i) by 4.
...(iii)
Subtracting (iii) from (ii), we get
Divide both sides by 12.90.
Put this value in (i).
The solution of system of equations is x=1.5 and y=2.75. It means, the yards of silk are 1.5 and yards of cotton are 2.75.
For every x you see in the f function you will replace with the h function
Answer:
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Step-by-step explanation:
The height h of the ball is modeled by the following equation
The problem want you to find the times the ball will be 48 feet above the ground.
It is going to be when:
We can simplify by 16t. So
It means that
16t = 0
t = 0
or
t - 2 = 0
t = 2
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.