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creativ13 [48]
3 years ago
9

. Reorder the following efficiencies from smallest to largest:

Computers and Technology
1 answer:
alexdok [17]3 years ago
3 0

Answer:

The order of the efficiencies is as following:-

10,000 < 2n < nlog(n) < n5 < n!.

Explanation:

10,000 is constant time whatever will be the size of the problem the efficiency will remain the same.

2n this efficiency is linear it will grow proportionally as the size of the problem increases.

nlog(n) this efficiency is is a bit greater than 2n though it will grow faster than 2n but slower than n2 as the size of the problem increases.

n5 this efficiency is very poor.It is growing very rapidly as the size of the problem increases.

n! is the worst efficiency of them all.

n!=n*(n-1)*(n-2)*(n-3)*(n-4)*.......2*1.

It will grow beanstalk in jack and the beanstalk.

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Answer:

//here is code in java.

import java.util.*;

class Solution

{

// main method of class

public static void main (String[] args) throws java.lang.Exception

{

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   }catch(Exception ex){

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}

}

Explanation:

declare and initialize two string variables.Create another string variable "st3". first assign value of "st1" to "st3" after then value of "st2" to "st1" and then  assign value of "st3" to "st2". This will exchange the values of both the string.

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