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3 years ago

6

The last term of an arithmetic sequence is 25, the common difference is 4, and the number of the terms is 9. What is the first t

erm?

1 answer:

Dafna11 [192]3 years ago

6 0

If you start at 25 and count down by 4, 8 times the answer you get is negative seven. so; -7, -3, 1, 5, 9, 13, 17, 21, 25.

You might be interested in

Solve for a: a(a-3) =100

marissa [1.9K]

$a(a-3) =100\\
a^2-3a-100=0\\
\Delta=(-3)^2-4\cdot1\cdot(-100)=9+400=409\\
\sqrt{\Delta}=\sqr{409}\\
a_1=\dfrac{-(-3)-\sqrt{409}}{2\cdot1}=\dfrac{3-\sqrt{409}}{2}\\
a_2=\dfrac{-(-3)+\sqrt{409}}{2\cdot1}=\dfrac{3+\sqrt{409}}{2}$

5 0

4 years ago

Help needed! no links please, they're annoying.

denis23 [38]

The area of a rectangle is length*width.

The length of this 3x and the width is 2x-3. This means that, to find the area, you need to multiply 3x and 2x-3.

Start by writing out this equation:
A=l*w

Then, plug in your given values:
A= 3x*2x-3 (you can also write it as A= 3*x*2*x-3)

Then, following the order of operations, you start by multiplying. This makes your equation become A = 6x^2 -3. (^2 means squared). It turns into this because 3 * 2 is 6 and x * x is x^2 and you still haven’t used the 3 yet.

After this, there is nothing more that you can do to simplify the equation. Therefore, the area is 6x^2 - 3.

I hope this helped!

4 0

3 years ago

What is the domain of the function y = 3 l n x graphed below? On a coordinate plane, a curve starts in quadrant 4 and then incre

VladimirAG [237]

Answer:

<h2>X greater-than 0</h2>

Step-by-step explanation:

The given function is

$y=3ln(x)$

Which is a logarithm function. An important characteristic of logarithms is that their domain cannot be negatice, because the logarithm of a negative number is undefined, the same happens for x=0.

Therefore, the domain of this function is all real numbers more than zero.

The image attached shows the graph of this function, there you can notice its domain restriction.

So, the right answer is the first choice: x greater than 0.

5 0

4 years ago

Cube-shaped blocks are packed into a cube-shaped storage container. The edge length of the storage container is 212 feet. The

igor_vitrenko [27]

Answer:

The volume of cube-shaped block is 0.125 cubic feet.

Step-by-step explanation:

We are given the following in the question:

Edge length of storage container =

$2\dfrac{1}{2}\text{ feet}$

Edge length of block =

$\dfrac{1}{5}\times \text{Edge length of container}$

Putting value we get,

Edge length of block =

$\dfrac{1}{5}\times 2\dfrac{1}{2}\\\\=\dfrac{1}{5}\times \dfrac{5}{2}\\\\=\dfrac{1}{2}\text{ feet}$

Volume of cube-shaped block = Volume of cube

$V = \text{(Edge)}^3\\\\V =(\dfrac{1}{2})^3\\\\V = \dfrac{1}{8}\text{ cubic feet}\\\\V = 0.125\text{ cubic feet}$

Thus, the volume of cube-shaped block is 0.125 cubic feet.

7 0

3 years ago

kramer

I think when you copied and pasted your question it re arranged itself

3 0

2 years ago