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3 years ago

Which is the best estimate for the length of a car

Mathematics

1 answer:

Greeley [361]3 years ago

8 0

The average length for a car would be 189 inches or 15 3/4 inches.

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What is the answer to 4x+y=10

Alina [70]

Answer:

y = -4x + 10

Step-by-step explanation:

I am going to assume you are trying to write the equation of a line.

4x + y = 10

4x - 4x + y = 10 - 4x

y = -4x + 10

7 0

3 years ago

In grade 7, the ratio of boys to girls is 14:24. How many more percentage is girls to boys?

klasskru [66]

Hi my name is bob plz give brainpower

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2 years ago

I am about to get my homework done I just need these two. (Thank you if you answer!!)

AnnZ [28]

Answer:

$-7=h\\-6.81=q$

Step-by-step explanation:

For question #1:

$-3=h+8/2\\-3=h+4\\-7=h$

For question #2:

$q+16.41=9.6\\q=-6.81$

8 0

1 year ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

Which of the following options have the same value as 65% of 20

Natasha2012 [34]

Answer:

Opt A and D

Step-by-step explanation:

65% is 100 based number, this means that 65% is the same as 65/100, or 0,65.

65% of 20 is obtained performing the following operation:

0,65 * 20

65*20/100

Any of them

7 0

3 years ago

Read 2 more answers