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Nuetrik [128]
2 years ago
6

does somebody knows how to do this one?

Mathematics
1 answer:
vlada-n [284]2 years ago
6 0

Answer:

Step-by-step explanation:

To find the area subtract the area of the semicircle from the area of the rectangle.

Although the line isn’t there, if you imagine there is one, then you will see that you form a rectangle which is the same line as the semicircle’s diameter.

The area of rectangle is:

⇒ A = lw

⇒ A = (14)(8)

⇒ A = 112cm^{2}

The area of the semicircle;

⇒ A = \frac{1}{2}\pi r^{2}

⇒ A = \frac{1}{2}\pi (7)^{2}

*Note here that the radius is half the diameter, so it is 7cm, not 14cm

⇒ A = 76.97cm^{2}

Finally subtract the two areas;

⇒ A = 112 - 76.97

⇒ A = 35.03cm^{2}

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Simplify each equation. Tell whether the equation has one, no, or infinite solutions. 3x-7=3(x-3)+2
STatiana [176]

Answer: Infinite solutions

Step-by-step explanation: 3x -7 = 3(x-3)+2

                                             3x + -7 = (3)(x) + (3)(-3) + 2

                                             3x + -7 = 3x + -9 + 2

                                             3x - 7 = (3x) + (-7)

                                             3x -7 - 3x = 3x - 7 - 3x

                                             -7 + 7 = -7 + 7

                                             0 = 0

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3 years ago
The municipal swimming pool in Nicetown has three different ways of paying for individual open swimming. Todd is trying to decid
balandron [24]
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3 years ago
What is the equation of the line that is parallel to y−5=−13(x+2) and passes through the point (6,−1)?
BartSMP [9]

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3 years ago
Solve the given inequality. Describe the solution set using the set builder or interval notation. Then graph the solution set on
Sophie [7]

Answer: THIRD OPTION.

Step-by-step explanation:

Given the following inequality:

3(x-5)\geq 6

You can follow these steps in order to solve it:

1. Apply Distributive property on the left side:

3(x-5)\geq 6\\\\(3)(x)+(3)(-5)\geq 6\\\\3x-15\geq 6

2. Add 15 to both sides of the inequality:

3x-15+(15)\geq 6+(15)\\\\3x\geq 21

3. Finally, divide both sides of the inequality by 3:

\frac{3x}{3}\geq \frac{21}{3}\\\\x\geq 7

 The symbol is \geq means "Greater than or equal to", and indicates that 7 is  include in the solution.

Therefore, the solution can be expressed as:

[7, \infty)

Now you must mark this point with a closed dot on the number line and shade everything to the right.

8 0
3 years ago
A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

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