Answer: Infinite solutions
Step-by-step explanation: 3x -7 = 3(x-3)+2
3x + -7 = (3)(x) + (3)(-3) + 2
3x + -7 = 3x + -9 + 2
3x - 7 = (3x) + (-7)
3x -7 - 3x = 3x - 7 - 3x
-7 + 7 = -7 + 7
0 = 0
Sllope intercept form is y=mx+b
m is the slope , b is the y itnercept
so early pay
cost=70 flat rate
x=infinity
the equation would be y=70
deposit pluss
you have to pay an initial one time payment of 15 so
y=mx+15
then 4 dollars per day
4 times number of days
y=4x+15
daily pay is 6 dollars per day so 6 times number of days
y=6x
1.
a. y=70
b. y=4x+15
c. y=4x
Answer:
y=-13x + 78 I'm not sure what's up with those answer choices though
Answer: THIRD OPTION.
Step-by-step explanation:
Given the following inequality:

You can follow these steps in order to solve it:
1. Apply Distributive property on the left side:

2. Add 15 to both sides of the inequality:

3. Finally, divide both sides of the inequality by 3:

The symbol is
means "Greater than or equal to", and indicates that 7 is include in the solution.
Therefore, the solution can be expressed as:
Now you must mark this point with a closed dot on the number line and shade everything to the right.
Answer:
is outside the circle of radius of
centered at
.
Step-by-step explanation:
Let
and
denote the center and the radius of this circle, respectively. Let
be a point in the plane.
Let
denote the Euclidean distance between point
and point
.
In other words, if
is at
while
is at
, then
.
Point
would be inside this circle if
. (In other words, the distance between
and the center of this circle is smaller than the radius of this circle.)
Point
would be on this circle if
. (In other words, the distance between
and the center of this circle is exactly equal to the radius of this circle.)
Point
would be outside this circle if
. (In other words, the distance between
and the center of this circle exceeds the radius of this circle.)
Calculate the actual distance between
and
:
.
On the other hand, notice that the radius of this circle,
, is smaller than
. Therefore, point
would be outside this circle.