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Vadim26 [7]
3 years ago
15

Pizza planet is running a speacial.3 pizzas for 16.50 what is the unit rate for one pizza

Mathematics
1 answer:
drek231 [11]3 years ago
6 0
For this you divide the total spent by the total number of pizzas...
16.50/ 3 = $5.50 per pizza.
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Which expression is equivalent to -7(y - 2)
Neko [114]

The expression equivalent to -7(y - 2) is -7y + 14

<h3>Which expression is equivalent to -7(y - 2)?</h3>

Given the expression; -7(y - 2)

We expand the expression by multiplying each element inside the parentheses the element out i.e -7

-7(y - 2)

[ -7 × y and -7 × -2 ]

-7y + 14

Therefore, the expression equivalent to -7(y - 2) is -7y + 14.

Learn more about expressions here: brainly.com/question/13947055

#SPJ1

5 0
1 year ago
The lakeside tour bus traveled 490 miles on saturday and 225 miles on sunday. About how many more miles did it travel on saturda
Monica [59]
490-225=265
Is the answer
8 0
3 years ago
Read 2 more answers
Classify the following triangle. Check all that apply
liq [111]

Answer:D and E are correect

Step-by-step explanation:

8 0
3 years ago
Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29
hram777 [196]

Answer:

\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }

Step-by-step explanation:

Hello,

I assume that we are working in \mathbb{C}, otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

   p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

So

\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }

Now, we need to find the zeroes of the second factor, meaning finding x so that:

x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4}  \\ \\  x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\  x = 2+5i \ \text{ or } \ x = 2-5i

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
Can somebody help me?
Vikentia [17]
9+3t is your answer.......
8 0
2 years ago
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