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2 years ago

By selling a cow for Rs 144, there is a profit of the same percentage as its cost price. Find the cost price.

Mathematics

2 answers:

Gekata [30.6K]2 years ago

6 0

Step-by-step explanation:

The cost price of cow =Rs80

hjlf2 years ago

4 0

Answer:

Step-by-step explanation:

<h2><u>☼︎</u><u>Answer:</u></h2>

The cost price of cow = Rs.80

Explanation:

<h2><u>☼︎</u><u>Given :-</u></h2>

By selling a cow for Rs 144, there is a profit of the same percentage as its cost price.

The cost price.

The cost price of cow = Rs.x

<h2><u>☼︎</u><u>Solution :-</u></h2>

$\sf x + x \: of \: x\%= 144 \\ \\ \sf \implies x + \frac{x \times x}{100} = 144 \\ \\ \sf \implies {x}^{2} + 100x - 14400 = 0 \\ \\ \sf \implies x(x - 80) + 180(x - 80) = 0 \\ \\ \sf \implies x + 180 = 0 \\ \\ \sf \implies x = - 180 \\ \\ \sf \therefore \: {\boxed{ \sf \pink{x = 80}}}$

<h2><u>Hence: </u></h2>

The cost price of cow =<u>R</u><u>s</u><u>8</u><u>0</u>

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Step-by-step explanation:

180 - 34 = 146

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180 - 62 = x

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The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe

juin [17]

The height of container is 8 feet

<em><u>Solution:</u></em>

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

<em><u>The volume of container is given as:</u></em>

$v = length \times width \times height$

Given that volume of the container is 216 cubic feet

$216 = l \times w \times h$

Substitute eqn 1 and eqn 2 in above formula

$216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0$

Solve by factoring

$(h-8)(h^2+4h+27) = 0$

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

$h - 8 = 0\\\\h = 8$

Also,

$h^2+4h+27 = 0$

Solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}$

$h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}$

Therefore, on solving we get,

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

<em><u>Thus solutions of "h" are:</u></em>

h = 8

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

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