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Paha777 [63]
4 years ago
9

Please help... i need it

Mathematics
2 answers:
Tanya [424]4 years ago
8 0
Oh ok .so the answer is.....2838384764733 I suggest the method of comparing variables
wel4 years ago
8 0

Answer:

the image isnt working

Step-by-step explanation:

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2. Brian is filling a conic container with water. He has the container half full. The radius of the container is 5 inches and th
MakcuM [25]

Answer:

current volume of the water = 785.714 in²

Height of new container = 10 inches

Step-by-step explanation:

Radius of the container = 5 inches

Height of the container = 20 inches

Volume of the container = πR²H = (22/7) × 5² × 20 = 1571.428571428 in²

Since the container is half filled with water, volume of the water = 1571.428571428 ÷ 2 = 785.714 in²

b. Volume of cylinder = πR²H = volume of water from first container = 785.714 in²

Hence 785.714 = (22/7) × 5² × H

H = (785.714) ÷ [(22/7) × 25] = 10 inches

Height of new container = 10 inches

5 0
4 years ago
Refers to an endless number of terms that follows a sequence and end with ellipsis
earnstyle [38]
Infinite sequence

I hope it helps
7 0
3 years ago
I understand the homework, but question 9. Could someone please help? This assignment is due on Friday (8/21/2020)
Valentin [98]

Answer:

I think B or C I'm not sure but I hope this helps!

Step-by-step explanation:

4 0
3 years ago
Latoya can paint five 10-foot-by-14-foot rooms by herself in 14 hours. Lisa can paint five 10-foot-by-14-foot rooms by herself i
Elina [12.6K]
Let's say if both work together, they can do it in "t" hrs

so, if Latoya can do it by herself in 14hrs, how much can she do in 1hr? well, she can do only 1/14 of the total

if Lisa can do it in 10hrs by herself, how much can she do in 1hr? well, 1/10 of the total

now, let's add their rate together, keeping in mind, their rate added, will be doing in 1hr only 1/t of the total work

thus \bf \cfrac{1}{14}+\cfrac{1}{10}=\cfrac{1}{t}\implies \cfrac{5+7}{70}=\cfrac{1}{t}\implies \cfrac{12}{70}=\cfrac{1}{t}\implies \cfrac{6}{35}=\cfrac{1}{t}
\\\\\\
t=\cfrac{35\cdot 1}{6}\implies t=\cfrac{35}{6}\implies t=5\frac{5}{6}

so, they'd do it in 5hrs and 5/6 of an hour, which is just 50mins, so, 5hrs and 50mins
8 0
3 years ago
Wayne's service center operates a welding shop. Assume that the arrival of jobs follows a Poisson distribution with 2 jobs arriv
Reika [66]

Answer:

a) 0.3125 per hour

b) 2.225 hours

c) 8.9 hours

d) 12.1 hours

e) 80%

Step-by-step explanation:

Given that:

mean time = 3.2 hours, standard deviation (σ) = 2 hours

The  mean service rate in jobs per hour (λ) = 2 jobs/ 8 hour = 0.25 job/hour

a) The average number of jobs waiting for service (μ)= 1/ mean time = 1/ 3.2 = 0.3125 per hour

b) The average time a job waits before the welder can begin working on it (L) is given by:

L=\frac{\lambda^2\sigma^2+(\lambda/\mu)^2}{2(1-\lambda/\mu))} =\frac{0.25^2*0.2^2+(0.25/0.3125)^2}{2(1-0.25/0.3125)}=2.225\ hours

c) The average number of hours between when a job is received and when it is completed (Wq) is given as:

W_q=\frac{L}{\lambda}=2.225/0.25=8.9\ hours

d) The average number of hours between when a job is received and when it is completed (W) is given as:

W=W_q+\frac{1}{\mu} =8.9+\frac{1}{0.3125}=12.1 \ hours

e) Percentage of the time is Gubser's welder busy (P) is given as:

P=\frac{\lambda}{\mu}=0.25/0.3125=0.8=80\%

4 0
3 years ago
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