Please help... i need it
2 answers:
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Let's say if both work together, they can do it in "t" hrs
so, if Latoya can do it by herself in 14hrs, how much can she do in 1hr? well, she can do only 1/14 of the total
if Lisa can do it in 10hrs by herself, how much can she do in 1hr? well, 1/10 of the total
now, let's add their rate together, keeping in mind, their rate added, will be doing in 1hr only 1/t of the total work
thus
so, they'd do it in 5hrs and 5/6 of an hour, which is just 50mins, so, 5hrs and 50mins
so, if Latoya can do it by herself in 14hrs, how much can she do in 1hr? well, she can do only 1/14 of the total
if Lisa can do it in 10hrs by herself, how much can she do in 1hr? well, 1/10 of the total
now, let's add their rate together, keeping in mind, their rate added, will be doing in 1hr only 1/t of the total work
thus
so, they'd do it in 5hrs and 5/6 of an hour, which is just 50mins, so, 5hrs and 50mins
Answer:
a) 0.3125 per hour
b) 2.225 hours
c) 8.9 hours
d) 12.1 hours
e) 80%
Step-by-step explanation:
Given that:
mean time = 3.2 hours, standard deviation (σ) = 2 hours
The mean service rate in jobs per hour (λ) = 2 jobs/ 8 hour = 0.25 job/hour
a) The average number of jobs waiting for service (μ)= 1/ mean time = 1/ 3.2 = 0.3125 per hour
b) The average time a job waits before the welder can begin working on it (L) is given by:
c) The average number of hours between when a job is received and when it is completed (Wq) is given as:
d) The average number of hours between when a job is received and when it is completed (W) is given as:
e) Percentage of the time is Gubser's welder busy (P) is given as: