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VikaD [51]
3 years ago
6

A rhombus and a square have one and the same side of 6 cm. The area of the rhombus is 4/5 of the area of the square. Find the he

ight of the rhombus. I will give the first person who told me how they got the answer and if it was correct the BRAINLEST answer, thx
Mathematics
1 answer:
Scilla [17]3 years ago
7 0
The area of the square= bxh
= 6x6= 36
The area of the rhombus is 4/5 the area of the square so 36x 4/5 = 28.8
Area of rhombus = basexheight
28.8= 6x height
Height = 28.8/6
Height =4.8
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cluponka [151]

Answer:

Part A: No it is not a function

Part B: The equation

Part C: x = 3

Step-by-step explanation:

Part A - The table:

Input (x)    Output (y)

6                14

12               15

15               15

25              16

This is a function because it has no repeating inputs values which have alternate outputs. Each input is assigned exactly one output.

Part B - The relation y = 7x - 15 has the value y = 27 when x = 6. You can find it by substituting into the equation.

y = 7(6) -15

y = 42 - 15

y = 27

The value of the relation in the table when x = 6 is y = 14. The equation has the greater value.

Part C: To find when y = 6, set it equal to 6 and solve for x.

6 = 7x - 15

21 = 7x

3 = x

5 0
3 years ago
PLZZZZZ HELP ME!<br> It’s math btw
matrenka [14]

Answer:

1. 9/10

2. 15/16

4. 3/5

5. 3/5

Step-by-step explanation:

1. 7/10 + 2/10 = 9/10

2. 13/16 + 2/16 = 15/16

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5. 9/20 + 3/20 = 12/20 = 3/5

3 0
3 years ago
Read 2 more answers
Great tennis players use Hexrackets. There if you use a Hexracket, you are a great tennis nyer.
34kurt

Answer:

The conclusion is invalid.

The required diagram is shown below:

Step-by-step explanation:

Consider the provided statement.

Great tennis players use Hexrackets. Therefore, if you use a Hexracket, you are a great tennis player.

From the above statement we can concluded that Great tennis players use Hexrackets. But it may be possible that some people who use a haxracket are not great tennis player.

Therefore, the conclusion is invalid.

The required diagram is shown below:

8 0
3 years ago
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enot [183]

Hello!

To solve this, first perform the opposite operation for the last operation (on the left side) on both sides. The last operation of the left side is squaring. Therefore, square root both sides.

(y - 9)^{2}  = 64

y - 9 = ±\sqrt{64}

y - 9 = ±8

Please note that you must include ±. This is because the square root of 64 can be either positive or negative, as a square of either a positive or negative number is positive.

Now, add 9 to both sides.

y  = 9±8

There are 2 solutions from here. One comes from adding 8, and the other subtracting 8. Therefore, the two solutions are:

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Therefore, your two solutions are 17 and 1.

Hope this helps!

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tester [92]

Answer:

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Step-by-step explanation:


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