If the length of rectangular school hall is 4 times the width and the perimeter be 55m, then the length is 22m and the width of the school hall be 5.5m.
Given that the length of rectangular school hall is 4 times the width.
We are required to find the length and breadth of the rectangle which has the length be 4 times the width.
Perimeter of rectangle is the sum of all the length and breadth of that rectangles.
Perimeter of rectangle is given as 55m
Perimeter=2(L+B)
let the width of rectangle be x.
Length of that rectangle be 4x.
According to question,
2(x+4x)=55
2*5x=55
10x=55
x=55/10
x=5.5 m
Width be 5.5 m.
Length of rectangle be 4*5.5=22m.
Hence if the length of rectangular school hall is 4 times the width then the length is 22m and the width of the school hall be 5.5m.
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30,12,6,6,36 there you go
Answer:
-4
Step-by-step explanation:
Absolute value is the distance from one number to the next, so it can't be negative. I-7+3I is 4.
- * 4 is equivalent to -1 * 5 so the answer is -4.
The answer should be 2+5+n.
Answer:
B because they are the same angle