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Dmitrij [34]
3 years ago
11

You are cleaning out your aunt’s basement and you find an IBM PC 5150, in its original box, with all its parts, and in working o

rder! Your aunt says that you are welcome to take it with you, since she forgot she even had it. Using the depreciation function, what is the PC 5150 worth this year? Does this seem like a reasonable amount? Explain.
Mathematics
1 answer:
MariettaO [177]3 years ago
5 0

Answer:yeah it seems like a reasonable amount.

Step-by-step explanation:

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Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal
Usimov [2.4K]

Answer:

a) We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

b) We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

Step-by-step explanation:

Part a

We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

Part b

We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

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3 years ago
For the polynomial below, find F(0.5). Round your answer to the nearest hundredth.
alexdok [17]
No it is not correct the answer is 14!

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3 years ago
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Lesechka [4]

The riddle answer is 24.

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2 years ago
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Find the 4 angles and the measure of are abd
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Answer:

Angle 1 = 80 (by definition)

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So Anglee 4 = 50

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3 years ago
Look at the number line below.
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3 years ago
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