All categories

3 years ago

What is the equation of a horizontal line passing through the point (−7, 5)? (1 point)

1 answer:

6 0

If it’s a horizontal line, we focus on the y-coordinates.

(-7,5)

-7 is a x-coordinate
5 is a y-coordinate

The answer is y = 5

You might be interested in

Maggie ebought 52 ounces of swordfish selling for $6.92 per pund. What was the total cost?

UNO [17]

The total cost was $22.49

3 0

3 years ago

Triangle ABC is formed by two parallel lines and two other intersecting lines. Find the measure of each angle A, B, and of the t

Mamont248 [21]

Answer:

A = 61°

B = 72°

C = 47°

Step-by-step explanation:

Well, first of all, we can see that:

$61^{\circ}+47^{\circ}+B^{\circ}=180^{\circ}$

So, we can find angle B.

$B=180^{\circ}-47^{\circ}-61^{\circ}$

$B=72^{\circ}$

Now, we can see to that angle C is just 47°

Finally, we know that the sum of all angles in a triangle is 180°, so we have:

$B+A+C=180^{\circ}$

$A=180^{\circ}-47^{\circ}-72^{\circ}$

$A=61^{\circ}$

I hope it helps you!

6 0

3 years ago

Chad casts a shadow that is 14.3 feet long. The straight-line distance from the top of Chad’s head to the end of the shadow crea

Elan Coil [88]

Imagine right triangle with first leg to be the Chad length and second leg to be the Chad's shadow. Second leg has length 14.3 ft and since the straight-line distance from the top of Chad’s head to the end of the shadow creates a 23° angle with the ground, you could consider the trigonmetric function

$\tan 23^{\circ}= \dfrac{\text{Chad's length}}{\text{Chad's shadow length}}$ ,

then $\tan 23^{\circ}= \dfrac{\text{Chad's length}}{14.3}, \\ \text{Chad's length}=14.3\cdot \tan 23^{\circ}=6.1$ .

4 0

3 years ago

How do I solve this problem -3(-4-6y)+7(-y+5)=-8

SOVA2 [1]

Answer:

y=-5

Step-by-step explanation:

-3(-4-6y)+7(-y+5)=-8

12+18y-7y+35=-8

11y+47=-8

11y=-8-47

11y=-55

y=-55/11

y=-5

4 0

4 years ago

5x - Зу = -7

sergeinik [125]

Answer:

I think elimination method will the the beat and easiest method we can use in that question,

4 0

3 years ago