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3 years ago

What is the equation of a horizontal line passing through the point (−7, 5)? (1 point)

1 answer:

6 0

If it’s a horizontal line, we focus on the y-coordinates.

(-7,5)

-7 is a x-coordinate
5 is a y-coordinate

The answer is y = 5

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Please don't delete my question! Here they are:

Alinara [238K]

Answer:

1. 14/15

2. 5 7/8

3. 81.25%

Step-by-step explanation:

1. (fraction) 7/9 divided by 5/6 (fraction)

7/9 ÷ 5/6 =

= 7/9 * 6/5

= (7 * 6)/(9 * 5)

= 42/45

= 14/15

1 3/8 + 4 1/2 =

= 1 + 3/8 + 4 + 1/2

= 1 + 4 + 3/8 + 4/8

= 5 + 7/8

= 5 7/8

percent = part divide by whole times 100

13/16 * 100 =

= 81.25%

4 0

3 years ago

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W hich of the following are you not likely to see on a graph? dependent variable, units, independent variable, prediction ...?

nekit [7.7K]

"Prediction" is the one among the following choices given in the question that you are not likely to see on a graph. The correct option among all the options that are given in the question is the fourth option or the last option. I hope that this is the answer that has actually come to your desired help.

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3 years ago

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There were 976 students that attended assemblies on bullying prevention throughout the

AveGali [126]

Answer:

245+368=?-976

Step-by-step explanation:

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3 years ago

A rectangular garden is divided into four sections. Some dimensions are shown in the diagram, and the distance

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Answer:7

Step-by-step explanation:

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3 years ago

Can someone please help me on number 16-ABC

melomori [17]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

-2x < 10

-6 < -2x

Part a) Is x = 0 a solution to both inequalities

FOR -2x < 10

substituting x = 0 in -2x < 10

-2x < 10

-3(0) < 10

0 < 10

TRUE!

Thus, x = 0 satisfies the inequality -2x < 10.

∴ x = 0 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 0 in -6 < -2x

-6 < -2x

-6 < -2(0)

-6 < 0

TRUE!

Thus, x = 0 satisfies the inequality -6 < -2x

∴ x = 0 is the solution to the inequality -6 < -2x

Conclusion:

x = 0 is a solution to both inequalites.

Part b) Is x = 4 a solution to both inequalities

FOR -2x < 10

substituting x = 4 in -2x < 10

-2x < 10

-3(4) < 10

-12 < 10

TRUE!

Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

-6 < -2(4)

-6 < -8

FALSE!

Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

solving -2x < 10

$-2x\:$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)>10\left(-1\right)$

Simplify

$2x>-10$

Divide both sides by 2

$\frac{2x}{2}>\frac{-10}{2}$

$x>-5$

$-2x-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}$

solving -6 < -2x

-6 < -2x

switch sides

$-2x>-6$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)$

Simplify

$2x$

Divide both sides by 2

$\frac{2x}{2}$

$x$

$-6$

Thus, the two intervals:

$\left(-\infty \:,\:3\right)$

$\left(-5,\:\infty \:\right)$

The intersection of these two intervals would be the solution to both inequalities.

$\left(-\infty \:,\:3\right)$ and $\left(-5,\:\infty \:\right)$

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

<h3>SUBSTITUTING x = 1</h3>

FOR -2x < 10

substituting x = 1 in -2x < 10

-2x < 10

-3(1) < 10

-3 < 10

TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

7 0

3 years ago