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iogann1982 [59]
3 years ago
12

work out the equation of the line which passes through the point(-1,2)and is parallel to the line y=x+4

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
3 0
If you have graph paper (or regular paper, graph is easier) you can plot it out. The equation would be y=x-1
just graph the point and then go up one over one until you get cross the y-axis
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What is the following equation formed when completing the square on Y^2-12y=-27
Salsk061 [2.6K]

Answer:y^1=3 ,y^2=9 if im wrong sorry im wrong but hope you get an a




7 0
3 years ago
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Help please asap will mark brainliest!
Andrew [12]

Answer:

VW = 7

Step-by-step explanation:

Because it is a parallelogram, UX = VW

x-4 = 2x - 15

11 = x

VW = 2 x 11 - 15

VW = 7

6 0
3 years ago
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30 &gt; -6(2X +3)<br> show me how to solve
MA_775_DIABLO [31]
<h3><u>x > -4 is the solution to this inequality.</u></h3>

30 > -6(2x + 3)

Distributive property.

30 > -12x - 18

Add 18 to both sides.

48 > -12x

Divide both sides by -12.

(Because we're dividing by a negative, the inequality sign flips.)

<h3><u>4- < x</u></h3>
6 0
3 years ago
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Nora and Lila are reading the same novel for book club.
stich3 [128]

Answer:

<u>1. Nora and Lila be on the same page of the book after 6 days and a half.</u>

<u>2. Nora and Lila be on the page 180.</u>

Step-by-step explanation:

1. Let's check the information given to resolve the question:

Current page of the novel that Nora is reading now = 128

Pages per day Nora reads = 8

Current page of the novel that Lila is reading now = 102

Pages per day Lila reads = 12

Days ahead for Nora and Lila will be on the same page = x

2. After how many days of reading will Nora and Lila be on the same page of the book?

128 + 8x = 102 + 12x

8x - 12x = 102 - 128 (Subtracting 12x and 128 at both sides)

-4x = -26

x = 6.5

<u>Nora and Lila be on the same page of the book after 6 days and a half.</u>

<u>3.</u> What page will they be on?

Nora : 128 + 8 (6.5) = 128 + 52 = 180

Lila : 102 + 12 (6.5) = 102 + 78 = 180

<u>Nora and Lila be on the page 180</u>

4 0
3 years ago
Help solving this math question
olga_2 [115]

22. B) $65,000,000 per year.

23. B) Education.

Step-by-step explanation:

Step 1; To find the average rate of change in annual budget between the two given years. We divide the difference in values for the two years by the period in between the two years. In 2008, the budget was $358,708,000 while in 2010 it was $488,106,000. The period in between was 2 years i.e 2009 and 2010.

The average rate of change = \frac{488,106,000-358,708,000}{2} = \frac{129,398,000}{2} = $64,699,000 per year.

So the average rate of change was $64,699,000 which approximately equals option B. $65,000,000.

Step 2; To find the human resources program's 2007 to 2010 ratio we divide the value in 2007 to the value in 2010. To find the other similar ratio, we divide the value in 2007 to the value in 2010 for all the other programs and determine which is closest to the human resources program.

Human resources program ratio = \frac{4,051,050}{5,921,379} = 0.6841,

Agricultural / natural resources ratio = \frac{373,904}{488,106} = 0.766,

Education's ratio = \frac{2,164,607}{3,008,036} = 0.7196,

General government's ratio = \frac{14,347,325}{14,716,155} = 0.9749,

Highways and transportation's ratio = \frac{1,468,482}{1,773,893} = 0.827,

Public safety's ratio = \frac{263,463}{464,233} = 0.5675.

The Human resources' program ratio is 0.6841 and the closest is Education's ratio which is 0.7196. So education is the answer.

4 0
3 years ago
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