How do I draw a shaded figure that represents 100%

The width of a rectangle is the length minus 7 units. The area of the

AleksandrR [38]

Answer:

8 units

Step-by-step explanation:

here's your solution

=> let the length of rectangle be X

=> then width = x - 7

=> area = 8units

=>> area = length*width

=> area = x (x-7) = 8

=> x^2 - 7 = 8

=> now, x^2 - 7x - 8 = 0

=> factories the above equation by middle term split

=> x^2 - 7x - 8

=> x^2 - 8x + x - 8

=> take the common

=> x(x - 8) + 1(x - 8)

=> (x + 1) (x - 8)

neglect (x + 1) because this will in negative for X

=> x - 8 = 0

=> x = 8

=>so, x = 8

=>length = 8 units

3 0

2 years ago

Help me find the arc length of this. Thank you.

BabaBlast [244]

The red chord is a diameter of the circle, so the length of the blue arc is half the circle's circumference.

The circumference of a circle with diameter $d$ is $\pi d$ , so the circle has circumference $8\pi$ , and so the arc has length $4\pi$ .

4 0

4 years ago

Given: circle k(O), m∠P=95°, m∠J=110°, m∠LK=125° Find: m∠PJ

IRINA_888 [86]

Answer:

The measure of the arc PJ is $75\°$

Step-by-step explanation:

step 1

Find the measure of angle L

we know that

In a inscribed quadrilateral opposite angles are supplementary

so

$m$

we have

$m$

substitute

$m$

step 2

Find the measure of arc KJ

we know that

The inscribed angle measures half that of the arc comprising

so

$m$

substitute the values

$95\°=\frac{1}{2}(125\°+arc\ KJ)$

$190\°=(125\°+arc\ KJ)$

$arc\ KJ=190\°-125\°=65\°$

step 3

Find the measure of arc PJ

we know that

The inscribed angle measures half that of the arc comprising

so

$m$

substitute the values

$70\°=\frac{1}{2}(65\°+arc\ PJ)$

$140\°=(65\°+arc\ PJ)$

$arc\ PJ=140\°-65\°=75\°$

5 0

3 years ago

What’s is the answer

kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

$(x^{2} )^{3} = x^6$

$(x^{3} )^5=x^{15}$

When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

$(x^{2} )(x^{3})=x^{5}$

$(x^{1} )(x^{2})=x^{3}$

$(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}$

You multiply 3 into each exponent in the numerator and the denominator

$\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

$\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}$

When you have something like this:

$\frac{x^{2}}{x^5}$

You subtract the exponents together, so:

$\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}$

Your answer is the second option

3 0

3 years ago

What shape is the base? What is the area of the base (B)?

VladimirAG [237]

Answer:

rectangular; 32 in²

Step-by-step explanation:

The base is rectangular, because 1 set of sides is longer than the other.

To find the area of the base, multiply 4 by 8 to get 32 in².

6 0

3 years ago