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3 years ago

I will mark brainliest if correct please answer fast I will give 10 points to the first person who answers

Mathematics

1 answer:

attashe74 [19]3 years ago

4 0

Answer:

$99\ in^{2}$

Step-by-step explanation:

Area of any triangle could be always calculated as base length multiplied by the height perpendicular to the aforementioned base divided by 2. Therefore:

A = 18 * 11 / 2 = 198 / 2 = 99

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Answer:

Domain (-4,6)

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

pls give brainliest

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arlik [135]

Given:

In a right angle triangle θ is an acute angle and $\tan\theta =\dfrac{3}{5}$ .

To find:

The value of $\cos \theta$ .

Solution:

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

We have,

$\tan\theta =\dfrac{3}{5}$

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

$Hypotenuse=\sqrt{Perpendicular^2+base^2}$

$Hypotenuse=\sqrt{(3x)^2+(5x)^2}$

$Hypotenuse=\sqrt{9x^2+25x^2}$

$Hypotenuse=\sqrt{34x^2}$

$Hypotenuse=x\sqrt{34}$

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

$\cos \theta=\dfrac{5x}{x\sqrt{34}}$

$\cos \theta=\dfrac{5}{\sqrt{34}}$

Therefore, the value of $\cos \theta$ is $\dfrac{5}{\sqrt{34}}$ .

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2 years ago