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Debora [2.8K]
3 years ago
10

Use the substitution method to solve the system of equations.

Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

D. (1/4, -2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -8x

4x - y = 3

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                    4x - (-8x) = 3
  2. Simplify:                               4x + 8x = 3
  3. Combine like terms:           12x = 3
  4. Isolate <em>x</em>:                              x = 3/12
  5. Simplify:                               x = 1/4

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define equation:                    y = -8x
  2. Substitute in <em>x</em>:                       y = -8(1/4)
  3. Multiply:                                  y = -2
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Answer:

The margin of error for constructing a 95% confidence interval on the population mean income before taxes of all consumer units in the U.S is 1406.32.

Step-by-step explanation:

We are given that according to a survey of 500, the mean income before taxes of consumer units (i.e., households) in the U.S. was $60,533 with a standard error of 717.51.

Margin of error tells us that how much our sample mean value deviates from the true population value.

<u></u>

<u>Margin of error is calculated using the following formula;</u>

        Margin of error =  Z_(_\frac{\alpha}{2}_) \times \text{Standard of Error}

where, \alpha = level of significance = 1 - confidence level

                                                    = 1 - 0.95 = 0.05 or 5%

Standard of Error =  \frac{\sigma}{\sqrt{n} } = 717.51

Now, the value of z at 2.5% level of significance (\frac{0.05}{2} =0.025) is given in the z table as 1.96, that means;

            Margin of error =  Z_(_\frac{\alpha}{2}_) \times \text{Standard of Error}

                                      =  1.96 \times 717.51 = 1406.32

Hence, the margin of error for constructing a 95% confidence interval on the population mean income before taxes of all consumer units in the U.S is 1406.32.

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