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raketka [301]
3 years ago
6

Does sin (-30) equal -sin (30)?

Mathematics
1 answer:
Ivan3 years ago
4 0

Answer:

Step-by-step explanation:

I dont know, sin (-30) might be an error because measures can’t be negative...

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Yolanda receives a $1,000 dollar raise each year from her starting salary of $40,800.
RUDIKE [14]

Answer:50,400

Step-by-step explanation:

5 0
3 years ago
Solve for X<br><br> Thank youuu
maksim [4K]

Answer:

x= -4

Step-by-step explanation:

∠LMP + ∠PMN= 180° (adj. ∠s on a str. line)

-16x +13 -20x +23= 180

bring x term to 1 side, constant to the other:

-36x= 180 -13 -23

Simplify:

-36x= 144

x= 144 ÷ (-36)

x= -4

*The sum of the angles on a straight line is 180°

6 0
3 years ago
a guy walks into a store and steals a $100 bill from the register without the owners knowldge. He then buys $70 worth of goods u
Elanso [62]
He lost $30 bc
Guy stole $100
Guy gave back $70
Owner gives hue $30 !
If that makes any sense ‍♀️
8 0
3 years ago
Mathematics, Help, not sure about my answer on this one
olga nikolaevna [1]

Answer:

F. 2 1/9

Step-by-step explanation:

Step 1: Substitute q

r = 3(\frac{1}{3^n} )+2

When you plug in <em>n</em> = 1, 2, 3:

n(1) = 3

n(2) = 2.11111

n(3) = 2.3333

So our answer is F.

3 0
3 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
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