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otez555 [7]
3 years ago
13

Jeffrey is playing a game with the two spinners below in the attachment:

Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0
Your answer would be C.
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(4a - 3b + 4c) + (8a - 2b + 3c)
Monica [59]

Answer:

<em>Hey mate, here's ur answer:</em>

<em>----------------------------------------------------------</em>

<em>(4a - 3b + 4c) + (8a - 2b + 3c)</em>

=4a+−3b+4c+8a+−2b+3c

=(4a+8a)+(−3b+−2b)+(4c+3c)

<u>=12a−5b+7c</u>

----------------------------------------------------------

<em>Hope it helps</em>

<em>#stayhomestaysafemate</em>

<em>:D</em>

5 0
3 years ago
Suppose the radius of a circle is 8. What is its area?
monitta
The Formula to find the Area of a circle using the radius is:
A =  \pi r^2

r = 8
So:
A =  \pi r^2
A =  \pi 8^2
A = \pi64

And you get about 201.06193

So, the area of a circle with a radius of 8 is about 201.06

Hope this Helps :)

3 0
3 years ago
Brian flips a fair coin 3 times. What is the probability of getting exactly 2 tails?
sammy [17]

Answer:

3/8

Step-by-step explanation:

The possible outcomes

TTT TTH THT THH  HHH HHT HTH HTT  = 8 outcomes

There are TTH THT HTT  3 with exactly two tails

P ( exactly 2 tails) = 3/8

7 0
3 years ago
Read 2 more answers
How to write (0,8] as an inequality
larisa86 [58]
Answer: 0 \ \textless \  x \le 8

What is given to you is interval notation. We have the interval start at 0 and end at 8. The value 0 is not included in the interval as indicated by the parenthesis. So we go with a "less than" sign (instead of a "less than or equal to" sign)

The value 8 is included since a square bracket is used here. The use of "or equal to" is needed to make sure the endpoint 8 is included.

So x can be any number between 0 and 8. It can't be 0 but it can be 8. 
3 0
3 years ago
If [x] denotes the least integer greater than or equal to x and [x/2] = 0, which of the following could be the value of x?A. -2B
podryga [215]

Answer:

B) -3/2

Step-by-step explanation:

If [x/2]=0 then x/2 is a number such that the least integer greater than or equal to x/2 is 0. We can rewrite this as the inequality x/2≤0. Then, the value of x in C, D and E is wrong because they are positive numbers, then x/2 would be a positive number which contradicts this inequality.

Now, 0 is the least integer that satisfies this inequality, therefore we cannot have that x/2≤-1 since -1 is an integer and -1<0. Then x/2>-1. This discards A as wrong, because for x=-2, x/2=-1, contrary to x/2>-1.

Thus B is the right answer. To verify, if x=-3/2, then x/2=-3/4 and we have that -1<-3/4≤0 as required.

3 0
3 years ago
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