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nirvana33 [79]
3 years ago
15

Suppose the radius of a circle is 8. What is its area?

Mathematics
1 answer:
monitta3 years ago
3 0
The Formula to find the Area of a circle using the radius is:
A =  \pi r^2

r = 8
So:
A =  \pi r^2
A =  \pi 8^2
A = \pi64

And you get about 201.06193

So, the area of a circle with a radius of 8 is about 201.06

Hope this Helps :)

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Ben needs to read 450 pages of his book for school. If he has five days to finish, how many pages should he read each day?
ehidna [41]

Answer: 90

Step-by-step explanation:

450/5 or 450 divided by 5

you can work this out by figuring out 45/5 which is 9

so 450/5 equals 90

he should read 90 pages per day

6 0
3 years ago
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1000divided by 27 what is the answer
olganol [36]
The rounded answer is 37.04
4 0
3 years ago
Can you help me fill in the blanks?
liberstina [14]

Answer:

Step-by-step explanation:

In Δ ABC & ΔADC

AC bisect ∠BCD           given

∠ACB ≅ ∠ACB                   AC bisect ∠BCD  

DC ⊥ AD                        Given

BC ⊥ AB                        Given

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3 0
3 years ago
A square building with an area of 225 m2 has a garden surrounding it that has an equal width on all sides. The area of the garde
xenn [34]

Answer:

The width of the garden is 1.16 m

Step-by-step explanation:

step 1

<em>Find the area of the garden</em>

To find out the area of the garden multiply by 1/3 the area of the building

225(\frac{1}{3})=75\ m^2

step 2

Find the length side of the square building

The area of a square is

A=b^2

where

b is the length side of the square

we have

A=225\ m^2

so

b^2=225\\b=15\ m

step 3

Find the width of the garden

Let

x ----> the width of the garden

we know that

The area of the building plus the area of the garden is equal to

(15+2x)^2=225+75

solve for x

225+60x+4x^2=225+75\\4x^2+60x-75=0

Solve the quadratic equation by graphing

using a graphing tool

The  solution is x=1.16 m

see the attached figure

therefore

The width of the garden is 1.16 m

Find the exact value

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

4x^2+60x-75=0  

so

a=4\\b=60\\c=-75

substitute in the formula

x=\frac{-60\pm\sqrt{60^{2}-4(4)(-75)}} {2(4)}

x=\frac{-60\pm\sqrt{4,800}} {8}

x=\frac{-60\pm40\sqrt{3}} {8}

x=\frac{-60+40\sqrt{3}} {8}\ m  ----> exact value

8 0
3 years ago
HELP!!!! Due tomorrow don't get
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On all of them? Which  numbers?

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