All categories

3 years ago

a garden snail moves 1/8 foot in 3/10 minute. What is the garden snail's rate of movement in feet per minute

Mathematics

2 answers:

Sindrei [870]3 years ago

5 0

1/8 / 3 = 1/8 x 1/3 = 1/24 of a foot every 1/10 minute

1/24 x 10 = 10/24 = 5/12 foot per minute

const2013 [10]3 years ago

5 0

Answer: 1/8 foot * 1/3 = 1/24 of every 1/10 minute

then, 1/24 * 10 = 10/24 or 5/12

You might be interested in

A hot air balloon hovers above its launch site at an altitude of 100 meters. The pilot of the balloon sights a parking lot at a

IgorLugansk [536]

Answer:

The horizontal distance between the parking lot and the launch site is 470 meters

Step-by-step explanation:

Let

x-----> the horizontal distance between the parking lot and the launch site

we know that

The tangent of angle of 12 degrees is equal to divide the altitude of 100 meters by the horizontal distance

tan(12°)=100/x

Solve for x

x=100/tan(12°)=470 meters

6 0

3 years ago

Look at the attachment<br>Simplified it too <br>pls take it seriously

Phantasy [73]

$\\ \rm\rightarrowtail \dfrac{sin(180+A)+2cos(180+A).cos(A-180)}{2cos^2(360+A)-cos(-A)}$

$\\ \rm\rightarrowtail \dfrac{-sinA+2(cos^2A-sin^2A)}{2cos^2A-cosA}$

$\\ \rm\rightarrowtail \dfrac{-sinA+2cos^2A-2sin^2A}{cosA(2cosA-1)}$

$\\ \rm\rightarrowtail \dfrac{-sinA+2-2sin^2A-2sin^2A}{cosA(2cosA-1)}$

$\\ \rm\rightarrowtail \dfrac{-sinA-4sin^2A}{cosA(2cosA-1)}$

$\\ \rm\rightarrowtail \dfrac{-sinA(4sinA-1)}{cosA(2cosA-1)}$

$\\ \rm\rightarrowtail -tanA\left(\dfrac{4sinA-1}{2cosA-1}\right)$

5 0

2 years ago

The volume of a cube is 1000cm3. Find:

Gala2k [10]

Length of one edge is 10cm
And the surface area is 600cm2

5 0

3 years ago

Read 2 more answers

Aziraphale bought books to be shipped to his library, in case they got out of stock. He bought 36 books, each having a total of

anzhelika [568]

Answer:

216

Step-by-step explanation:

36 times 10 = 360

360 times 0.60 = 216

3 0

3 years ago

Three moons are in the same circular orbit around a planet. The moons are each 115,000 kilometers from the surface of the planet

marshall27 [118]

275,000 km
The moons A, B, C form a right triangle with AC forming a hypotenuse with the diameter of the planet and the distance of both moons from the surface. So add A to the surface, plus the diameter of the planet, plus surface to c.
115000+45000+115000 = 275000

7 0

3 years ago

Read 2 more answers