<span>If the triangle has an obtuse angle (>90 degrees), it can be classified as an obtuse triangle Not sure where the 42 inches is used Hope this helps</span>
Answer:
R=-12
Step-by-step explanation:
6(1 + 3R) = 2(10R - 9) -4R
Distribute 6 through the parentheses
6+18R=2(10R-9)-4R
Distribute 2 through the parentheses
6+18R=20R-18-4R
Collect like terms
6+18R=16R-18
Move the variable to the left-hand side and change its sign
6+18R-16R=-18
Move the constant to the right-hand side and change its sign
18R-16R=-18-6
Collect like terms
2R=-18-6
Calculate the difference
2R=-24
Divide both sides of the equation by 2
R=-12
if you'd make me brainliest that'd be great, if not its ok as well! I hope this helped!!!
Answer:
15° and 100°
Step-by-step explanation:
3 × 5 = 15, 20 × 5 = 100. So the other two angles measure 15° and 100°.
Let's work on the left side first. And remember that
the<u> tangent</u> is the same as <u>sin/cos</u>.
sin(a) cos(a) tan(a)
Substitute for the tangent:
[ sin(a) cos(a) ] [ sin(a)/cos(a) ]
Cancel the cos(a) from the top and bottom, and you're left with
[ sin(a) ] . . . . . [ sin(a) ] which is [ <u>sin²(a)</u> ] That's the <u>left side</u>.
Now, work on the right side:
[ 1 - cos(a) ] [ 1 + cos(a) ]
Multiply that all out, using FOIL:
[ 1 + cos(a) - cos(a) - cos²(a) ]
= [ <u>1 - cos²(a)</u> ] That's the <u>right side</u>.
Do you remember that for any angle, sin²(b) + cos²(b) = 1 ?
Subtract cos²(b) from each side, and you have sin²(b) = 1 - cos²(b) for any angle.
So, on the <u>right side</u>, you could write [ <u>sin²(a)</u> ] .
Now look back about 9 lines, and compare that to the result we got for the <u>left side</u> .
They look quite similar. In fact, they're identical. And so the identity is proven.
Whew !
The correct answer for the question that is being presented above is this one:
We need to express the ksp expression of C2D3
<span>C2D3
= (2x)2(3x)3
= 108x5 </span>
<span>Then set that equation equal to your solubility constant </span>
<span>9.14x10-9 = 108x5 </span>
<span>x = 9.67x10-3
</span>
<span>So the molar solubility is 9.67x10-3</span>
