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castortr0y [4]
3 years ago
15

Complete the square for x^2 + 6x + ? to form a perfect square trinomial

Mathematics
1 answer:
Georgia [21]3 years ago
8 0
To complete the square, or finding the c constant of this trinomial to make it factor evenly, use this formula to find the c constant (as according to the quadratic equation ax^2+bx+c):
(b/2)^2

When you plug in the b value, 6, you should get this:
(6/2)^2

Then, when you simplify, you get a result of 9 which would be the missing constant to fill in your trinomial. When you plug it in, you should get this as your final trinomial:

x^2+6x+9
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A triangle with 118° and 42 in. is what type of triangle?
tankabanditka [31]
<span>If the triangle has an obtuse angle (>90 degrees), it can be classified as an obtuse triangle Not sure where the 42 inches is used Hope this helps</span>
3 0
3 years ago
Read 2 more answers
6(1 + 3R) = 2(10R - 9) -4R
Damm [24]

Answer:

R=-12

Step-by-step explanation:

6(1 + 3R) = 2(10R - 9) -4R

Distribute 6 through the parentheses

6+18R=2(10R-9)-4R

Distribute 2 through the parentheses

6+18R=20R-18-4R

Collect like terms

6+18R=16R-18

Move the variable to the left-hand side and change its sign

6+18R-16R=-18

Move the constant to the right-hand side and change its sign

18R-16R=-18-6

Collect like terms

2R=-18-6

Calculate the difference

2R=-24

Divide both sides of the equation by 2

R=-12

if you'd make me brainliest that'd be great, if not its ok as well! I hope this helped!!!

5 0
3 years ago
One angle of a triangle measures 65°. The other two angles are in a ratio of 3:20. What are the measures of those two angles?
Nataly_w [17]

Answer:

15° and 100°

Step-by-step explanation:

65 + 3x + 20x = 180

23x = 115

x = 5

3 × 5 = 15, 20 × 5 = 100. So the other two angles measure 15° and 100°.

3 0
2 years ago
Prove the following identity :<br>Sin α . Cos α .<br> Tan α =  (1 – Cos<br> α)  (1 + Cos<br> α)
Umnica [9.8K]
Let's work on the left side first. And remember that
the<u> tangent</u> is the same as <u>sin/cos</u>.

sin(a) cos(a) tan(a)

Substitute for the tangent:

[ sin(a) cos(a) ] [ sin(a)/cos(a) ]

Cancel the cos(a) from the top and bottom, and you're left with

[ sin(a) ] . . . . . [ sin(a) ] which is [ <u>sin²(a)</u> ]  That's the <u>left side</u>.

Now, work on the right side:

[ 1 - cos(a) ] [ 1 + cos(a) ]

Multiply that all out, using FOIL:

[ 1 + cos(a) - cos(a) - cos²(a) ]

= [ <u>1 - cos²(a)</u> ] That's the <u>right side</u>.

Do you remember that for any angle, sin²(b) + cos²(b) = 1  ?
Subtract cos²(b) from each side, and you have sin²(b) = 1 - cos²(b) for any angle.

So, on the <u>right side</u>, you could write [ <u>sin²(a)</u> ] .

Now look back about 9 lines, and compare that to the result we got for the <u>left side</u> .

They look quite similar. In fact, they're identical. And so the identity is proven.

Whew !





4 0
3 years ago
Read 2 more answers
C2d3 has a solubility product constant of 9.14×10−9. what is the molar solubility of c2d3?
UkoKoshka [18]
The correct answer for the question that is being presented above is this one:

We need to express the ksp expression of C2D3
<span>C2D3
= (2x)2(3x)3
= 108x5 </span>

<span>Then set that equation equal to your solubility constant </span>

<span>9.14x10-9 = 108x5 </span>
<span>x = 9.67x10-3 
</span>
<span>So the molar solubility is 9.67x10-3</span>
4 0
3 years ago
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