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4 years ago

Complete the square for x^2 + 6x + ? to form a perfect square trinomial

1 answer:

8 0

To complete the square, or finding the c constant of this trinomial to make it factor evenly, use this formula to find the c constant (as according to the quadratic equation ax^2+bx+c):
(b/2)^2

When you plug in the b value, 6, you should get this:
(6/2)^2

Then, when you simplify, you get a result of 9 which would be the missing constant to fill in your trinomial. When you plug it in, you should get this as your final trinomial:

x^2+6x+9

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Evaluate 32 + (7- 2.4<br> .<br> (1 point)<br> 3<br> 24<br> 28<br> 54<br> 27

zhuklara [117]

Answer:

27 is your answer.

<h3>Hope it helps you!!</h3>

7 0

3 years ago

Please help! 2 math problems about slope intercept form

Bezzdna [24]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

(1)

Given

y - 3 = - 2(x + 5) ← distribute parenthesis

y - 3 = - 2x - 10 ( add 3 to both sides )

y = - 2x - 7 ← in slope- intercept form

(2)

y = 3x + 5 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{3}$ , thus

y = - $\frac{1}{3}$ + c ← is the partial equation

To find c substitute (3, - 2) into the partial equation

- 2 = - 1 + c ⇒ c = - 2 + 1 = - 1

y = - $\frac{1}{3}$ x - 1 ← equation of line

8 0

3 years ago

A word processing program requires a user to enter a 7-digit registration code made up of the digits 1,2,4,5,6,7 and 9. Each num

ahrayia [7]

For the first digit there are 7 choices. For the second digit there are 6 choices (because we can't use the same one again). And so on, until there is only one choice for the last digit.

The number of possible codes is this:
7*6*5*4*3*2*1 = 7! = 5040

6 0

3 years ago

2=2/m−7. what is M?

r-ruslan [8.4K]

Answer:

The answer is m = 8

Step-by-step explanation:

2 = 2/(m−7)

2(m-7) = 2

m-7 = 1

m = 1+7

m = 8

4 0

4 years ago

A year on mars is 1.88 times as long as a year n Earth.An Earth year lasts 365.3 days.Find the legth of a year on mars.

Kazeer [188]

I got 686.764 days for a year on Mars your welcome

8 0

3 years ago