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FrozenT [24]
3 years ago
15

Ronald and Tim did their laundry today. Ronald does laundry every 6 days and Tom does laundry every 9 days. How many days will i

t be until Ronald and Tim do their laundry on the same day again?
Mathematics
1 answer:
Luden [163]3 years ago
7 0
Least common multiple question

Ronald: count by 6's
 6, 12, 18, 24, 30, 36, 42, 48, 54 ....

Tim: count by 9's
9, 18, 27, 36, 45, 54,

every 18 days they do their laundry together
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Kayla and he children went into a restaurant and she bought $63 worth of hotdogs and tacos. Each hotdog costs $3.50 and each tac
Diano4ka-milaya [45]

Answer:

Kayla bought 7 tacos and 10 hotdogs

Step-by-step explanation:

Let the number of hotdogs be x.

Let the number of tacos be y.

i) It is given that x = y + 3

ii) It is also given that 3.5x + 4y = 63, therefore 7x + 8y = 126

iii) substituting the value of x from i) in ii) we get 7(y + 3) + 8y = 126

   therefore 15y + 21 = 126

 therefore 15y = 105

  therefore y = 7

  Therfore Kayla bought 7 tacos

iv) Using the value of y from iii) in i) we x = 7 + 3 = 10

  Therefore Kayla bought 10 hotdogs

6 0
2 years ago
Whats the indicated operation?
Black_prince [1.1K]
4/11 * 10/8
= 1/11 * 10/2
= 1/11 * 5
= 5/11

answer 5/11
you got it correct
7 0
3 years ago
A family went out to dinner and the cost of the food was $80. If the tip given was 15%, what
barxatty [35]
It should be $92.00

80 • .15 = 12
so 15% of the total ($80) is 12.

add the 12 to the total 80+12= $92
8 0
2 years ago
Read 2 more answers
How many significant digits are there in the measurement 0.09584 kg?
Vesnalui [34]
Four as zeros don't count when you're figuring out significant figures
8 0
3 years ago
The u.s. department of health and human services collected sample data for 772 males between the ages of 18 and 24. that sample
soldier1979 [14.2K]
The 99% confidence interval for the true mean is given by:

\bar{x}\pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

where: 

\bar{x} is the sample mean = 69.7
\sigma is the standard deviation = 2.8
z_{\alpha/2} is the test statistics = 2.58 for for 99% confidentce interval.
n is the sample size = 772.

Therefore, the 99% confidence interval is:

69.7\pm2.58\left( \frac{2.8}{\sqrt{772}} \right)=69.7\pm2.58(0.1008) \\  \\ =69.7-0.26\leq\mu\leq69.7+0.26 \\  \\ =69.44\leq\mu\leq69.96
6 0
2 years ago
Read 2 more answers
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