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svet-max [94.6K]
3 years ago
13

Which fraction is equivalent to 0.16 the 6 is repeating. Please show the work .

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
4 0
The answer would be 1/6.

To show work, you can just divide 1 by 6. This would give you the answer of 0.166666666...
sergiy2304 [10]3 years ago
3 0

Answer:

Answer is 1/6

Step-by-step explanation:

To convert  1/6 to decimal, just divide 1 by 6  

(That's what the fraction is showing; a fraction = numerator  ÷ denominator)  

1 ÷ 6 = 0.16666666 ...

So that is  1 6  in decimal form!

( 0.16 recurring)  

Note that per in percent means each and  perc e n t  means 100.

Therefore, percentage is just the quantity out of  100

! Simple!

So, multiply the decimal form of  

1 6  by  100

(That is why I did decimal first)

0.16666666 ...  ·(x) 100  =  16.66666 ... ... . %

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3 years ago
A. 1/3=0.33<br>B. 1/6=0.17<br>C. 1/10=0.10<br>D. 1/4=0.25​
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A manufacturer of computer printers purchases plastic ink cartridges from a vendor. When a large shipment is received, a random
g100num [7]

Answer:

97.4% probability

Step-by-step explanation:

Since there is only two possible outcome of inspecting the catridge : either defective or not, we can solve the problem using the binomial probability distribution (approximated to normal).

To approximate the binomial probability to normal, we find the expected value and the standard deviation of the probability of exactly x sucesses on n repeated trials with p probability

Expected values E(X) = np

Standard deviation √V(X) = √np(1-p)

using the z-score formula (X - μ)/σ, we can solve normally distributed problem.

Where μ is the mean and σ is the standard deviation. The Z-score is is the measure of how much a sample is from the mean. The p-value associated with this z-score which is the probability that the value of the measure is smaller than X can be checked on the z-score table.

FOR THIS QUESTION,

a random sample of 200 cartridges is selected

n = 200

Therefore If there are more than 0.02 × 200 = 4 defective, the sample will be returned.

To determine the approximate probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05

μ = E(X)

= 0.05 × 200 = 10

σ = √V(X) = √np(1-p)

= √200 × 0.05 × 0.95

= 3.08

This probability is 1 subtracted by the pvalue of Z when X =4

Z = (X - μ)/σ

Z= (4 - 10)/3.08

Z = -1.95

Z = -1.95 has a P-value of 0.026 (on the z-score table)

This means that there is a 1 - 0.026 = 0.974

= 97.4% probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05.

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Answer:

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